按名称显示数据库中的图像 [英] display image from database by name
本文介绍了按名称显示数据库中的图像的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有数据库
`image_name`, `caption`, `image`, `username`
我想在数据库中按照他的名字显示图像(image_name)我有这个代码错误,图像没有显示
I want to display the image according his name in database(image_name)I have this code the error in it the image is not show
<?php
require_once("db.php");
session_start();
$username = $_SESSION['username'];
$sql = "SELECT * from photo2 WHERE Username='$username'";
$result = mysql_query($sql) or die (mysql_error());
$numrows = mysql_num_rows ($result);
if($numrows!=0)
{
while ($found_ids = mysql_fetch_assoc($result))
{
echo "<tr><td align='center'> $found_ids[image_name]</a></td> </tr>";
//echo "<img src=get.php?id=$found_ids[ID]";
}
}
$id = addslashes($_REQUEST['image_name']);
$image = mysql_query("SELECT * FROM photo2 WHERE image_name=$id");
$image = mysql_fetch_assoc($image);
$image = $image['Photodata'];
header ("Content-type: image/jpeg");
echo $image;
?>
推荐答案
username =
username =
_SESSION [' username'< /跨度>];
_SESSION['username'];
sql = SELECT * from photo2 WHERE Username ='
sql = "SELECT * from photo2 WHERE Username='
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