JavaScript对象被推入数组 [英] JavaScript object pushed into an array

问题描述

可能重复：

我如何正确克隆一个JavaScript对象？

我有这段代码：

  var temp = []; 
 var obj = {name：1}; 
 temp.push（obj）; 
 obj.name =2; 
 temp.push（obj）; 
  

我期待的是真实的：

  temp [0] .name ==1&& temp [1] .name ==2; 
  

实际发生的事情：

  temp [0] .name ==2&& temp [1] .name ==2; 
  

为什么会发生这种情况，以及我如何得到我期待的结果？

解决方案

JavaScript数组包含对象的引用，而不是对象本身。将对象推入数组时，它不会创建新对象，但它只是将对象的引用（ obj 也指向）放入数组中。 / p>

所以最后obj，temp [0]和temp 1 都指向同一个对象。要实际创建一个全新的对象，您可以使用对象.create（）或jQuery.extend（{}，obj）。虽然在你的情况下，只需使用 var newobj = {name =2}

创建一个新的简单对象就够了

Possible Duplicate:
How do I correctly clone a JavaScript object?

I have this code:

var temp = [];
var obj = {name:"1"};
temp.push(obj);
obj.name = "2";
temp.push(obj);

What I'm expecting to be true:

temp[0].name == "1" && temp[1].name == "2";

What actually happens:

temp[0].name == "2" && temp[1].name == "2";

Why does this happen, and how I can get what I'm expecting?

解决方案

JavaScript arrays hold references to objects, rather than objects themselves. When you push an object into the array it does not create a new object, but it simply puts a reference to the object, that obj also points to, into the array.

So in the end obj, temp[0], and temp1 all point to the same object. To actually create a completely new object, you can use Object.create() or jQuery.extend({},obj). Though in your case it's easy enough just to create a new simple object using var newobj = {name="2"}

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