如何在php中传递Sql参数？ [英] How to pass the Sql Parameter in php?
本文介绍了如何在php中传递Sql参数？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我写了加入查询
喜欢
$ connectionInfo = array（Database=>nsdf）;
$ conn = sqlsrv_connect（$ serverName，$ connectionInfo）;
$ result = sqlsrv_query（$ conn，SELECT CodeValue.Name，CodeValue.Latitude，CodeValue.Longitude，Area.Type，Area.Description
FROM CodeValue
INNER JOIN区域
ON CodeValue.Id = Area.fk_SlumId）;
如何传递这些值
??
I written the Join Query
like
$connectionInfo = array( "Database"=>"nsdf");
$conn = sqlsrv_connect($serverName, $connectionInfo);
$result= sqlsrv_query($conn,"SELECT CodeValue.Name,CodeValue.Latitude,CodeValue.Longitude, Area.Type,Area.Description
FROM CodeValue
INNER JOIN Area
ON CodeValue.Id=Area.fk_SlumId");
How to pass these values
??
推荐答案
connectionInfo = array（Database=>nsdf）;
connectionInfo = array( "Database"=>"nsdf");
conn = sqlsrv_connect（
conn = sqlsrv_connect(
serverName，
serverName,
这篇关于如何在php中传递Sql参数？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
查看全文
