为什么JavaScript split()会使用不同的变量名生成不同的输出? [英] Why does JavaScript split() produce different output with different variable names?
问题描述
以下是Chrome开发者控制台的一些代码和输出
Following is some codes and output from the Chrome Developers' Console
案例1:
var myarr = document.location.hostname.split("."); //typed
undefined //output
myarr[0] //typed
"ptamz" //output: ONE
案例2:
var name = document.location.hostname.split("."); //typed
undefined //output
name[0] //typed
"p" //output: TWO
为什么两个输出(注释输出:ONE和输出:TWO)不同?
Why are the two outputs (commented Output: ONE, and Output: TWO) different?
屏幕截图:
推荐答案
name
是 window
的属性。看来,当您尝试将该属性设置为数组时,键将以逗号连接(调用 toString
)。所以你实际上是将 window.name
属性设置为 document.location.hostname.split(。)的每个元素的串联
,以逗号分隔。
name
is a property of window
. It appears that when you try to set that property to an array, the keys are joined with a comma (the result of calling toString
on an array). So you are actually setting the window.name
property to the concatenation of each element of document.location.hostname.split(".")
, separated by commas.
这是我的Chrome控制台的屏幕截图,展示了会发生什么:
Here's a screenshot from my Chrome console demonstrating what happens:
原因 name [0]
然后结果 p
是你可以使用方括号访问字符串的字符:
The reason name[0]
then results in p
is that you can access the characters of strings using square brackets:
name = "hello,world";
console.log(name[0]); //"h"
修改
正如其他人所提到的,这只是全球范围内的情况。您可以在后代范围内声明名为 name
的变量。虽然,在这种情况下,省略 var
关键字仍会导致您访问 window.name
:
As others have mentioned, this will only be the case in the global scope. You are free to declare a variable named name
inside a descendant scope. Although, obviously, omitting the var
keyword in this case would still result in you accessing window.name
:
function example() {
var name = ["hello", "world"];
console.log(name); //["hello", "world"]
}
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