查找扩展基类的Javascript应用程序中的所有类 [英] Find all classes in a Javascript application that extend a base class
问题描述
我有这样的代码
class Animal{}
class Dog extends Animal {}
class Cat extends Animal {}
class Donkey extends Animal {}
我想看看我的应用程序的Universe中的所有类,当我找到一个来自Animal的类时,我想创建一个该类型的新对象并将其添加到列表中。这允许我添加功能而无需更新事物列表。所以我可以避免以下情况:
I want to look at all of the classes in my application's universe, and when I find one that descends from Animal, I want to create a new object of that type and add it to the list. This allows me to add functionality without having to update a list of things. So I can avoid the following:
var animals = [];
animals.push( new Dog() );
animals.push( new Cat() );
animals.push( new Donkey() );
PS:我不想在我的类中添加额外的功能或明确地调用它们。
PS: I don't want to add extra functionality to my classes or call them explicitly.
推荐答案
这是我到目前为止所发现的
http://jsbin.com/xiroyurinu/1/edit?js,console,output
Here what I discovered so far http://jsbin.com/xiroyurinu/1/edit?js,console,output
class Animal{}
class Dog extends Animal {}
class Cat extends Animal {}
class Donkey extends Animal {}
var animals = getAllSubclasses(Animal);
console.log(animals.map(function(c){ return new window[c] })) // creates objects
document.body.innerText = animals; // Dog, Cat, Donkey
和魔法
function getAllSubclasses(baseClass) {
var globalObject = Function('return this')();
var allVars = Object.keys(globalObject);
var classes = allVars.filter(function (key) {
try {
var obj = globalObject[key];
return obj.prototype instanceof baseClass;
} catch (e) {
return false;
}
});
return classes;
}
这种方法的主要缺点是我无法使用ES6模块导入和必须做旧式和简单的文件连接,但这仍然更好,没有。
The main disadvantage of this method is that I can not use ES6 module import and have to do old fashioned and simple contatenation of files, but this is still better that nothing.
PS:仍在等待更好的答案
PS: still wait for better answer
UPD:我知道要使用这个必须全局定义所有类,这就是为什么我寻找更好的方法来做到这一点..
UPD: and ye, i know that to use this all classes must be defined globally, that's why i search for better way to do this..
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