VB.NET中Application.Restart（）的替代方法是什么？ [英] What is the Alternative to Application.Restart() in VB.NET ?

问题描述

如果我使用Application.Restart然后它关闭应用程序并且它不会立即启动新实例。为什么会这样？我正在使用visual studio 2012和.net 2.0。请给我一个解决方案。有没有其他方法来重新启动vb.net 2.0应用程序。

if i use Application.Restart then it's Shuts down the application and it does not start a new instance immediately. why it is happening ? i'm using visual studio 2012 and .net 2.0. Please give me a solution. is there any other way to restart vb.net 2.0 application.

Private Sub Button14_Click(sender As Object, e As EventArgs) Handles Button14.Click
        Application.Restart()
    End Sub

以下是ApplicationEvents.vb文件内容

Below is the ApplicationEvents.vb file content

Namespace My
    ' The following events are available for MyApplication:
    ' 
    ' Startup: Raised when the application starts, before the startup form is created.
    ' Shutdown: Raised after all application forms are closed.  This event is not raised if the application terminates abnormally.
    ' UnhandledException: Raised if the application encounters an unhandled exception.
    ' StartupNextInstance: Raised when launching a single-instance application and the application is already active. 
    ' NetworkAvailabilityChanged: Raised when the network connection is connected or disconnected.
    Partial Friend Class MyApplication
    End Class
End Namespace

推荐答案

重启失败的原因：

你在表单关闭事件上有一个事件可以阻止关闭/重启。

你有一个只允许单个应用程序实例的检查。



解决方案：在调用restart之前删除处理程序并删除单实例检查。



祝您好运！

Reasons for restart to fail:
You have an event on form close event that prevents shutdown/restart.
You have a check that allows only a single instance of the application.

Solution: Remove the handlers and remove the single instance check before calling restart.

Good luck!

原因很可能是您在应用程序启动代码中进行了单实例检查。显然应用程序必须在它仍在运行时重新启动，因此旧应用程序仍在运行且新实例正在启动的时间很短，但由于单实例检查而立即退出。我建议的解决方案：如果您的应用程序检测到已经运行的自身实例，请让它休眠1-2秒（或更长时间，如果您的应用程序需要时间关闭）并在延迟后再次检查 - 然后只有在其他实例仍在运行。

The reason is most probably that you have a single-instance-check in your application startup-code. Obviously the application has to restart itself while it is still running, so there's a small timeframe in which the old application is still running and the new instance is starting up, but immediately quitting because of that single-instance-check. My proposed solution: In case your application detects an already running instance of itself, let it sleep for 1-2 seconds (or longer, if your application needs time to shut down) and check again after that delay - and then only exit if the other instance is still running.

是的先生，我在表单关闭事件上有一个事件。我删除了那段代码。现在它工作正常。谢谢大家......非常感谢你。

Yes sir, i had an event on form close event. I removed that code. Now it's working fine. Thank u all... Thank u so much.

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