我该如何制作这种类型的矩阵？ [英] How do I make this type matrix?
问题描述
我希望代码能够做到这一点。我无法做到这一点。
我有一个向量和一个矩阵..
Facility_units = [4 2 3 1]
总计= 4 + 2 + 3 + 1 = 10
矩阵D =
[0 4 2 4;
4 0 1 3;
2 1 0 2;
4 3 2 0]
D是对称矩阵，其中对角线元素为0，上三角形类似于下三角形。
我想要这种形式的输出，例如
输出= 10 * 10矩阵即总计*总额
[
0 0 0 0 4 4 2 2 2 4;
0 0 0 0 4 4 2 2 2 4;
0 0 0 0 4 4 2 2 2 4;
0 0 0 0 4 4 2 2 2 4;
4 4 4 4 0 0 1 1 1 3;
4 4 4 4 0 0 1 1 1 3;
2 2 2 2 1 1 0 0 0 2;
2 2 2 2 1 1 0 0 0 2;
2 2 2 2 1 1 0 0 0 2;
4 4 4 4 3 3 2 2 2 0]
输出矩阵是10乘10，其中元素根据向量Facility_units重复。
第一个设施有4个单位，第二个有2个单位，第三个有3个单位，第四个有1个单位。
D是表示每个设施之间距离的矩阵。例如根据矩阵D（即距离矩阵），设施1和2之间的距离为4,1到3之间为2，1到4之间为4.
现在我想要输出显示设施的每个单元与任何其他单位之间的距离。例如具有距离0的相同设施的单位。第一设施有4个单位，这就是为什么在输出矩阵1：4行乘以1：4列为0.
比设施2的设备1的单位的距离是2.
ss（1）= 0;
for q = 2：number + 1
ss（q）= ss（q-1）+ facility_units（q-1）;
结束
ss
dist =零（tu，tu）;
表示i = 1：数字
表示j = 1：数字
如果di（i，j）〜= 0&&我〜= j&& i< j>
代表l = ss（j-1）+1：ss（j）
代表m = ss（j）+1：ss（j + 1）
dist（l，m）= di（i，j）;
结束
结束
代表l = ss（j）+1：ss（j + 1）
代表m = ss（j-1）+1：ss（j）
dist（l，m）= di（i，j）;
结束
结束
结束
结束
结束
dist
I want the code to make this. I am not able to make this.
I have one vector and one matrix..
Facility_units=[4 2 3 1]
total=4+2+3+1=10
matrix D=
[0 4 2 4 ;
4 0 1 3 ;
2 1 0 2 ;
4 3 2 0]
D is symmetric matrix in which diagonal element is 0 and upper triangle is similar to lower triangle.
I want the output in this form e.g.
output= 10*10 matrix i.e. total*total
[
0 0 0 0 4 4 2 2 2 4 ;
0 0 0 0 4 4 2 2 2 4 ;
0 0 0 0 4 4 2 2 2 4 ;
0 0 0 0 4 4 2 2 2 4 ;
4 4 4 4 0 0 1 1 1 3 ;
4 4 4 4 0 0 1 1 1 3 ;
2 2 2 2 1 1 0 0 0 2 ;
2 2 2 2 1 1 0 0 0 2 ;
2 2 2 2 1 1 0 0 0 2 ;
4 4 4 4 3 3 2 2 2 0 ]
output matrix is 10-by-10 in which elements are repeated according to vector Facility_units.
1st facility having 4 units, 2nd has 2 units, 3rd has 3 units and 4th has 1 unit.
D is the matrix shows the distance between each facility. e.g. distance between facility 1 and 2 is 4, between 1 and 3 is 2 and between 1 and 4 is 4. according to that matrix D (i.e. distance matrix) is made.
Now i want the output that shows the distance between each unit of the facility with any other units. e.g. units of same facility having distance 0. 1st facility have 4 units that is why in output matrix 1:4 row by 1:4 column is 0.
than distance of units of facility 2 with facility 1 is 2.
ss(1)=0;
for q=2:number+1
ss(q)=ss(q-1)+facility_units(q-1);
end
ss
dist=zeros(tu,tu);
for i=1:number
for j=1:number
if di(i,j)~=0 && i~=j && i<j>
for l=ss(j-1)+1:ss(j)
for m=ss(j)+1:ss(j+1)
dist(l,m)=di(i,j);
end
end
for l=ss(j)+1:ss(j+1)
for m=ss(j-1)+1:ss(j)
dist(l,m)=di(i,j);
end
end
end
end
end
dist
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