这是什么意思？ std :: istream response_stream（& * response_）; [英] What does it mean? std::istream response_stream(&*response_);

问题描述

我跟踪了其他人的C ++代码;包含一个声明

std :: istream response_stream（&* response_）;

其中response_定义为

boost :: asio :: streambuf * response_;



在回复之前对用户&和*有意义吗

&* response_

？



&* response_不等于'response _'？

I traced C++ codes from others; containing a statement
std::istream response_stream(&*response_);
where response_ is defined as
boost::asio::streambuf * response_;

Does it make sense to user & and * before response_ like
&*response_
?

Isn't "&*response_" equal to just 'response_'?

推荐答案

你没有添加太多的代码来澄清，但是因为它被写成它看起来像一个函数声明 - 在这种情况下它是有道理的。



将参数定义为&在c ++函数声明中意味着参数通过引用传递，如下一个示例中所示。

You did not add much code to clarify, but as it is written it looks like a function declaration - in that case it makes sense.

Defining a parameter as & in a c++ function declaration means that the parameter is passed by reference, as in the next example

void same(int &n);  // declaration of the prototype with a reference
int main(){
    int iA = 5;   // Define a number
    same(iA);     // pass the variable to ur function BY REFERENCE
    cout << iA; // Without the reference passing I should see 5; By reference I can 
                // change the value of the parameter, so now iA equals 6;
    return 0; // Exit from main
}
void same(int &n){
    n = 6;
}

所以通过传递一个参数作为& * response_我传递对象的引用响应指出_ 。



我希望我已经足够清楚了（英语不是我的主要语言）并帮助过你。



编辑：我发现了一篇关于CodeProject的文章指针指针和指针引用 [ ^ ]，也许对你有帮助。



- Denis

So by passing a parameter as &*response_ I'm passing a reference to the object pointed by response_.

I hope I have been clear enough (English is not my primary language) and to have helped you.

I found an article on CodeProject Pointer to Pointer and Reference to Pointer[^], maybe it helps you.

- Denis

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