首先尝试使用Python！ [英] First try at Python!

问题描述

各位大家好，我刚开始用Python编写代码。我之前没有任何其他编程语言的经验，所以我希望这个论坛对我来说是一个学习编码的好地方！所以这里是：

  import  random 
 
 bankroll =  10  
 bankroll2 =  10  
 
 < span class =code-keyword> def  player（）：
 player1 = random.randrange（ 0 ， 5 ）
 player2 = random.randrange（ 0 ， 5 ）
  if  player1> player2：
  print   播放器1抛出一个：，player1 
  print   玩家2抛出：，玩家2 
 打印  玩家1赢 
 bankroll +  1  
 bankroll2  -   1  
 打印 bankroll 
  print  bankroll2 
  elif  player1< player2：
  print   播放器1抛出一个：，player1 
  print   玩家2抛出：，玩家2 
 打印  玩家2赢 
 打印 bankroll 
 打印 bankroll2 
 其他：
  print   播放器1抛出：，player1 
  print   播放器2抛出：，player2 
  print   这是一个平局！ 
  print  bankroll 
  print  bankroll2 
  print    
 
 
 
 player（）
 player（）
 player（）
 player（） 
 player（）
 player（）
 player（）

现在资金总是重新启动到10，我理解为什么，但我不知道如何避免它。我的目标是跟踪资金。



如果有人能指出我正确的方向，我将不胜感激。

解决方案

以下语句只计算值

 bankrol1 +  1  
 bankroll2  -   1  

但这就是全部，他们不保存它们。它们应该是

 bankroll + =  1  ＃ 将1添加到bankrol1  
 bankroll2  -  =  1  ＃ 从bankroll2减去1  

您还需要为案例添加两个语句当player2获胜时。我想如下：

 bankrol1  -  =  1   ＃ 从bankrol1减去1  
 bankroll2 + =  1  ＃ 将1添加到bankroll2  

扩展到之前的回答，这归结为可变性。

基本上，整数是不可变的。添加两个整数时，它返回一个全新的整数。在这种情况下，您有一个变量bankroll，它被指定为原始整数。向此变量添加1时，该操作将返回一个新整数。你需要用更新的变量覆盖原始变量。

 ＃ 为变量指定一个整数 
 bankroll =  10  
 
 ＃ 我们会将其分开，以便于查看。 
 ＃ 基本上是bankroll + 1返回加法运算的结果 
 ＃ 我们现在将它存储到临时变量 
 temp = bankroll +  1  
 
 ＃ 使用 $ b的值覆盖原始bankroll变量$ b ＃ 临时变量 
 bankroll = temp 

现在我们合作请按以下方式在一行中执行此操作

 bankroll = bankroll +  1  

如果不使用临时变量，这会做同样的事情。但是，python有一些很好的语法糖来进行这种操作

 bankroll + =  1  

实际上这可用于许多基本操作

 bankroll =  10  
  print （bankroll）＃ 打印10  
 
 bankroll + =  1  
  print （bankroll）＃ 打印11  
 
 bankroll  -  =  1  
  print （bankroll）＃ 打印10  
 
 bankroll * =  2  
  print （bankroll）＃ 打印20  
 
 bankroll / =  2  
 打印（bankroll）＃ 打印10  

Hello everyone, i just started coding in Python. I have no prior experience in any other programming language so i hope this forum will be a great place for me to learn about coding! so here it is:

import random

bankroll = 10
bankroll2 = 10
    
def player():
    player1 = random.randrange(0, 5)
    player2 = random.randrange(0, 5)
    if player1 > player2:
        print "Player 1 throws a :", player1
        print "Player 2 throws a :", player2
        print "Player 1 Win"
        bankroll + 1
        bankroll2 -1
        print bankroll
        print bankroll2
    elif player1 < player2:
        print "Player 1 throws a :", player1
        print "Player 2 throws a :", player2
        print "Player 2 Win"
        print bankroll
        print bankroll2
    else:
        print "Player 1 throws a :", player1
        print "Player 2 throws a :", player2
        print "It's a tie!"
        print bankroll
        print bankroll2
    print ""
        
        
        
player()
player()
player()
player()
player()
player()
player()

right now the bankrolls are always restarting to 10, i understand why but i don't know how to avoid it. My goal is to keep track of the bankroll.

If anyone could point me in the right direction it would be greatly appreciated.

解决方案

The following statements just calculate the values

bankrol1 + 1
bankroll2 -1

but that is all, they do not save them. They should be

bankroll += 1    # add 1 to bankrol1
bankroll2 -= 1   # subtract 1 from bankroll2 

You also need to add two statements for the case when player2 wins. I would guess something like:

bankrol1 -= 1    # subtract 1 from bankrol1
bankroll2 += 1   # add 1 to bankroll2 

To extend on the previous answer, this comes down to mutability.
Basically, integers are immutable. When you add two integer it returns a brand new integer. In this case, you have a variable bankroll which is assigned to be the original integer. When you add 1 to this variable, the operation returns a new integer. You need to overwrite the original variable with the updated one.

# Assign an integer to your variable
bankroll = 10

# We'll separate this out for ease of viewing.
# basically bankroll + 1 returns the result of the addition operation
# We'll store it to a temp variable for now
temp = bankroll + 1

# Overwrite the original bankroll variable with the value of the
# temp variable
bankroll = temp

Now we could do this in one line as follows

bankroll = bankroll + 1

This does the same thing without using a temporary variable. However, python has some nice syntactic sugar for doing this sort of operation

bankroll += 1

In fact this are available for many of the basic operations

bankroll = 10
print(bankroll) # prints 10

bankroll += 1
print(bankroll) # prints 11

bankroll -= 1
print(bankroll) # prints 10

bankroll *= 2
print(bankroll) # prints 20

bankroll /= 2
print(bankroll) # prints 10

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