点击.net中的Clickonce问题 [英] Clickonce issue in .net

问题描述

这里我在.net中创建了一个应用程序，该应用程序将从该应用程序调用一个第三方.exe。所以我将.exe与我的应用程序一起包含并将属性设置为复制到输出dirctory =复制始终和构建操作=内容

i创建了一次此应用程序的单击，并且单击一次工作正常。



同一个应用程序给出了签名并创建了一次点击，但是clickonce不是工作文件，它显示错误

那个.exe已经存在在临时路径中





如何解决这个问题



在此先感谢

Here i created an application in .net and that application will call one third party .exe from that application. So i include that .exe along with my application and made property as Copy to out put dirctory=Copy always and Build Action=Content
i created a click once of this application, and the click once is working fine.

The same application a gave signing and create click once , but the clickonce is not working file , it shows an error that
"That .exe is already exists" in the temp path


How can i solve this issue

Thanks in advance

推荐答案

解决方案是：



保存。 exe在应用程序中并设置属性为复制到输出dirctory =嵌入式资源和构建操作=不复制





然后从代码当我们需要访问此.exe时，我们从项目资源中读取并写入本地驱动器位置并调用该.exe

The solution is :

Save the .exe in application and set property as Copy to out put dirctory=Embedded Resource and Build Action=Do not copy


Then from the code level when we need to access this .exe , we read from project resource and write to local drive location and call to that .exe

string exeName = "test.exe";
string dirName = Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location);
if (!System.IO.Directory.Exists(dirName)) System.IO.Directory.CreateDirectory(dirName);
string dllPath = System.IO.Path.Combine(dirName, exeName);
if (!File.Exists(dllPath))
{
    using (System.IO.Stream stm = Assembly.GetExecutingAssembly().GetManifestResourceStream("Assembly name where we save that exe" + "." + exeName))
    {
        // Copy the assembly to the temporary file
        try
        {
            using (System.IO.Stream outFile = System.IO.File.Create(dllPath))
            {
                const int sz = 4096;
                byte[] buf = new byte[sz];
                while (true)
                {
                    int nRead = stm.Read(buf, 0, sz);
                    if (nRead < 1)
                        break;
                    outFile.Write(buf, 0, nRead);
                }
            }
        }
        catch
        {
        }
    }
}

这里的dllPath是.exe，所以我们可以从代码中调用这个exe作为

Here in "dllPath" , is the .exe , so we can call this exe from code as

Process p = new Process();
p.StartInfo.Arguments = "coma separated arguments"
p.StartInfo.CreateNoWindow = false;
p.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
p.StartInfo.FileName = dllPath ;
p.Start();

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