创建并写入N个文本文件 [英] Create and write in N number of textfiles

问题描述

我的任务是创建一个程序，该程序将从文本文件中读取数字N并创建乘法表，最多为N.每个乘法表将被写入单独的单独文件中。该程序基本上会为文本文件创建N编号。

例如Table1.txt将包含

1 x 1 = 1

1 x 2 = 2

1 x 3 = 3

1 x 4 = 4

Table2.txt将包含

2 x 1 = 2

2 x 2 = 4

2 x 3 = 6

等等



到目前为止，我的代码看起来像这样，只会将所有乘法表打印成一个文本文件。

My assignment is to create a program that would read a number N from a textfile and create multiplication table up to N. Each multiplication table is to be written into separate a separate file. The program would essentially create N number for textfiles.
For example Table1.txt would contain
1 x 1 = 1
1 x 2 = 2
1 x 3 = 3
1 x 4 = 4
Table2.txt would include
2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
and so on

So far my code looks like this and will only print all the multiplication tables into one textfile.

#include <iostream>
#include <fstream>
using namespace std;

int main()
{
	//initializations
	int input, product;
	ifstream inputstream;
	ofstream outputstream;
	inputstream.open("input.txt");
	outputstream.open("output.txt");
	
	//Inputting the number from the text file.
	inputstream >> input;
	
	//Creating the multiplication tables
	for (int counter = 1; counter <= input; counter++)
	{	
		for (int counter2 = 1; counter2 <= input; counter2++)
		{
			product = counter * counter2;
			outputstream << counter << " x " << counter2 << " = " << product << endl; 
		}
		outputstream << "==========================================" << endl << "==========================================" << endl;
	}
	return 0;
}

我应该如何更改代码以获得作业要求的内容？我的初步猜测是将output.open（output.txt）放入循环中，但是当我这样做时，我只能得到一个具有1次表的文本文件，即使输入文件中的数字是10 。

How should I change my code to get what the assignment is asking for? My intial guess was to put the output.open("output.txt") into the loop but when I did that I was only able to get one text file which had the 1's times table even though the number in my input file was 10.

for (int counter = 1; counter <= input; counter++)
{
    outputstream.open("output.txt");
    for (int counter2 = 1; counter2 <= input; counter2++)
    {
        product = counter * counter2;
        outputstream << counter << " x " << counter2 << " = " << product << endl;
    }
    outputstream << "==========================================" << endl << "==========================================" << endl;
}

推荐答案

#include <iostream>
#include <sstream>

using namespace std;
int main(int argc, char *argv[])
{
    ostringstream filename;
    for (int i=0; i<10; i++)
    {
        filename.str("");
        filename << "Table" << i << ".txt";
        cout << filename.str() << endl;
    }

    return 0;
}

输出

Output

Table0.txt
Table1.txt
Table2.txt
Table3.txt
Table4.txt
Table5.txt
Table6.txt
Table7.txt
Table8.txt
Table9.txt

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