如何从下拉列表中选择值 [英] how to select value from dropdown list

问题描述

 <  表格   操作  =  search.php    方法  = 发布 >  
 <？ php 
 $ select_query =  从书籍中选择不同的类别; 
  $ select_query_run  = mysql_query（$ select_query）; 
 $ select_query_array = mysql_fetch_array（$ select_query_run）; 
  echo   < select name ='类别>中; 
  while （$ select_query_array = mysql_fetch_array（$ select_query_run））
 {
  //  动态下拉列表和值类似于cat1，cat2，cat3和cat4  
 
  echo   < option value =''> .htmlspecialchars（$ select_query_array [   category]）。 < span class =code-string>< / option>; 
} 
 
  echo   < /选择> 中; 
 ？>  
 <  < input     type   =  text    name   =  searchvalue    size   =  5      id   =  searchfield    title   =  searchfield    onFocus   =  clearText（this） < span class =code-keyword> /  >  
 <  输入    type   = 提交   姓名  = 提交    value   =     alt   = 搜索    id   =  searchbutton    title   = 搜索    /  >  
 <   / form  >  <  < span class =code-keyword>>  

SEARCH.PHP

我只是想打印实际用户从drop drown list中选择的值。我尝试下面的代码检查即使我尝试了SESSION但它没有打印任何值，请任何人帮助我。

 <？php  
  echo  $ _POST ['  category']; 
 ？>  

解决方案

select_query = 从书籍中选择不同的类别;

select_query_run = mysql_query（

select_query）;

<form action="search.php" method="post">
<?php
$select_query=          "Select distinct category from books";
$select_query_run =     mysql_query($select_query);
$select_query_array=   mysql_fetch_array($select_query_run) ;
 echo "<select name='category'>";
while ($select_query_array=   mysql_fetch_array($select_query_run) )
{
//dynamic dropdown list and values are like cat1,cat2,cat3 and cat4

   echo "<option value='' >".htmlspecialchars($select_query_array["category"])."</option>";
}

echo "</select>"; 
 ?>
   <<input type="text" name="searchvalue" size="5"  id="searchfield" title="searchfield" onFocus="clearText(this)"/>
     <input type="submit" name="submit" value="" alt="Search" id="searchbutton" title="Search" />
</form><>

SEARCH.PHP
I am just trying to print what value actually user selected from drop drown list.. I tried below code to check even I tried with SESSION but its not printing any value please anyone help me.

<?php
echo $_POST['category'];
?>

解决方案

select_query= "Select distinct category from books";

select_query_run = mysql_query(

select_query);

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