为什么数字在C中被舍入？ [英] How come number is being rounded in C?

问题描述

输出总是向上或向下舍入？而不是显示十进制浮点数？任何帮助都非常感谢！

谢谢！

这是代码：

The output always rounds up or down? instead of showing a decimal float? Any help is well appreciated!
Thanks!
Here is the code:

#include<stdio.h>
#include<conio.h>

 void DisplayInstructions();
 int CalculateAverage(int a,int b, int c);
 float DisplayAnswer(float ans);

 void main()
 {
     int Integer1 = 0, Integer2 = 0, Integer3 = 0;
     float answer;
     DisplayInstructions();
     scanf_s("%d", &Integer1);
     scanf_s("%d", &Integer2);
     scanf_s("%d", &Integer3);
     answer = CalculateAverage( Integer1, Integer2, Integer3);
     DisplayAnswer(answer);
     _getch();
 }

 void DisplayInstructions()
 {
     printf("Enter 3 Integers seperated by the ENTER key\n");
 }

 int CalculateAverage(int a, int b, int c)
 {
     float average, num = 3;
     average = ( a + b + c )/num;

     return average ;
 }

 float DisplayAnswer(float ans)
 {
     printf("Answer=%f\n", ans);
 }

推荐答案

如果您返回 int ，您会有什么期望？ ？将 int CalculateAverage 更改为 int CalculateAverage 。

-SA

What would you expect if you return int? Change "int CalculateAverage" to float "int CalculateAverage".

—SA

更改int CalculateAnswer以返回浮动。在printf中更改格式字符串为2个小数点。查看cplusplus.com了解详情。

Change int CalculateAnswer to return a float. In printf change format string for 2 decimal points. Look up cplusplus.com for details.

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