将字符串与整数连接起来 [英] concatenate a string with an integer

问题描述

嗨！



我想用一个整数连接一个字符串，这就是我使用这段代码的原因：

hi!

i want to concatenate a string with an integer that's why i used this code :

++k;
	    char f[50];
		sprintf(f,"%d",k);  
		strcat ( f,"N");

但我得到的是这个（例如： 1N ），我想要的是这样的事情： N1



你能帮帮我吗



谢谢verry muuuuch



晚安

but what i got is this ( for example :1N) and what i want is some thing like this : N1

Could you please help me with this

Thank you verry muuuuch

good night

推荐答案

解决这个问题你可以像@ Status BreakPoint一样使用说：sprintf（f，％s％d，N，k ）;'而不是strcat。



谢谢你Status BreakPoint

to solve this you can just use like @ Status BreakPoint said :sprintf(f, "%s%d", "N", k);' instead of strcat.

thank you "Status BreakPoint "

如果你真的有一个字符串（即在一个变量中），那么你可以简单地说：

If you truly have a string (ie. in a variable), then you can simply do:

sprintf(f, "%s%d", string, k);

其中'string'是变量，'k'是int值。



如果字符串是一个常量值（例如你的例子中的N），你可以将它简化为：

where 'string' is the variable and 'k' is the int value.

If the string is a constant value (eg. "N" as in your example) you can simplify it to:

sprintf(f, "N%d", k);

其中'k'是int值。



......实际上，上述两个sprintf（）实例都是sprintf_s （）如果你为我编写代码。

where 'k' is the int value.

... and really, both of the above instances of sprintf() will really be sprintf_s() if you write code for me.

只是为了记录 - 除非你有充分的理由去摆弄 sprintf 和C ++的C遗产的其他遗物一样，这种字符串摆弄的方法是使用 std :: stringstream ：

Just for the record - unless you've got a good reason to be fiddling about with sprintf and other relics of C++'s C heritage the way to the do this sort of string fiddling is to use a std::stringstream:

std::string stick_an_N_in_front_of_an_integer( int k )
{
    std::ostringstream formatter;
    formatter << "N" << k;
    return formatter.str();
}

如果你真的必须把所有藏在字符缓冲区中的东西都看看 std :: strstream 。它类似于 std :: stringstream ，但它的所有输出都改为原始字符缓冲区。

If you've really got to have everything tucked into a character buffer have a look at std::strstream instead. It's similar to std::stringstream but does all its output to a raw character buffer instead.

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