感谢任何身体将此函数反转回字节数组 [英] Thanks any body reverse this function back to byte array

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本文介绍了感谢任何身体将此函数反转回字节数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

private static string GetHexString(byte[] bt)
        {
            string s = string.Empty;
            for (int i = 0; i < bt.Length; i++)
            {
                byte b = bt[i];
                int n, n1, n2;
                n = (int)b;
                n1 = n & 15;
                n2 = (n >> 4) & 15;
                if (n2 > 9)
                    s += ((char)(n2 - 10 + (int)'A')).ToString();
                else
                    s += n2.ToString();
                if (n1 > 9)
                    s += ((char)(n1 - 10 + (int)'A')).ToString();
                else
                    s += n1.ToString();
                if ((i + 1) != bt.Length && (i + 1) % 2 == 0) s += "-";
            }
            return s;
        }

推荐答案

我不知道是谁编写的,但代码非常非常糟糕:效率极低。

特别是当.NET中有一个方法为你做这件事时: BitConverter.ToString [ ^ ]它将字节对与' - '分开。

当然,没有反向!但是,它非常简单:

I have no idea who wrote that, but it's very, very poor code: it is spectacularyly inefficient.
Particularly when there is a method in .NET to do that for you: BitConverter.ToString[^] it separates the byte pairs with '-' is all.
And of course, there isn't a reverse! But, it's pretty simple:
byte[] data = File.ReadAllBytes(@"D:\Temp\MyFile.bin");
string s = BitConverter.ToString(data).Replace("-", "");
byte[] data2 = new byte[s.Length / 2];
for (int i = 0; i < s.Length; i += 2)
    {
    byte b = (byte) (GetHex(s[i + 1]) | (GetHex(s[i]) << 4));
    data2[i / 2] = b;
    }
private byte GetHex(char c)
    {
    if (Char.IsDigit(c)) return (byte)(c - '0');
    return (byte)(c - 'A' + 10); 
    }


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