如何在Php中使用Oops定义数据库表名? [英] How Can I Define Database Table Name Using Oops In Php?
问题描述
我已经用这种方式定义
define('PAGES','admin_cms_page');
但它不能用于以下代码
$ id = $ _REQUEST ['id'];
$ res = $ obg-> select('PAGES','*','id ='。$ id);
$ res_userseditt = $ obg-> GetResult($ res);
如果我使用以下代码工作
$ id = $ _REQUEST ['id'];
$ res = $ obg-> select(' admin_cms_page','*','id ='。$ id);
$ res_userseditt = $ obg-> GetResult($ res);
请建议我。
id =
_REQUEST ['id'];
解析度=
I have define it in this way
define('PAGES','admin_cms_page');
but its not working in the following code
$id = $_REQUEST['id'];
$res=$obg->select('PAGES','*','id='.$id);
$res_userseditt=$obg->GetResult($res);
if i am using the following code its working
$id = $_REQUEST['id'];
$res=$obg->select('admin_cms_page','*','id='.$id);
$res_userseditt=$obg->GetResult($res);
please suggest me.
id =
_REQUEST['id'];
res=
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