如何调试此错误消息“Out arguments not a class of a variable”" [英] How do I debug this error message"Out arguments is not classified as a variable"

问题描述

我在编写的代码中出现此错误，使用方法执行初始值的公式

类似

< pre lang =c＃> public static double miuk;
public static double yp = 0 ;
私有 静态 double e_e = Exp（ ref 时间， out Yt（ out yp））; // 错误
private static double N1，N2，N3，N4 ，C1，C2，C3，C4;
私有 静态 double Exp1 =求和（ ref N1， ref C1， ref N2， ref C2， ref N3， ref C3， ref N4， ref C4）;

public static double SN（ ref double miuK， out double yp）
{
yp = 0 ;
// yp = Yt（ref miuK，out yp）;
< span class =code-keyword> return Xp * B * P *（（miuK *（1-Math.Exp（ - （e_e））） - 1）+（yp * Math.Exp（ - （ e_e））* EXP1））;

}

public static double Yt（ out double yp）
{
yp = 0 ;
return Xp * B * P * miuk *（ 1 - Math.Exp（ - （ e_e）））+（yp *（Math.Exp（ - （e_e））））;
}

如何赠送新款价值从重新回到哟一遍又一遍



任何一个有用的想法请其紧急。

解决方案

  private   static   double  e_e = Exp（ ref 时间， out  Yt（ out  yp））;  //   error  

您不能将 Yt（out yp）调用作为out参数传递。



out参数必须为变量或字段。它必须是可写的位置。



我不知道你的 Exp（...，... ..）方法是定义的。



（名称 类似于 Math.Exp（）不是一个好主意，特别是因为你在这段代码中也使用了 Math.Exp（）！）



显示 Exp（...，...）方法，我可以提供帮助...

看起来你真的不需要这么多的参数。





我不确定这个，因为我仍然不知道你实际上想要做什么。

如果你想 Yt 到< b>总是操作静态 yp 值，和总是更新它然后可能是这样的：

  public   static   double  Yt（）
 {
 yp = Xp * B * P * miuk *（ 1   -  Math.Exp（ - （e_e）））+（yp *（Math.Exp（ - （e_e））））; 
  return  yp; 
} 

否则，可能更像是：

  public   static   double  miuk; 
  public   static   double  yp = Yt（ 0 ）; 
 私有 静态  double  e_e = Exp（时间，yp）; 
 私有 静态  double  N1 ，N2，N3，N4，C1，C2，C3，C4; 
 私有 静态  double  Exp1 =求和（ ref  N1， ref  C1， ref  N2， ref  C2， ref  N3， ref  C3， ref  N4， ref  C4）; 
 
  public   static   double  SN（ ref   double  miuK， out   double  yp）
 {
  //  将这一项作为练习......;  - ） 
 yp =  0 ; 
  //   yp = Yt（ref miuK，out yp）;  
 < span class =code-keyword> return  Xp * B * P *（（miuK *（1-Math.Exp（ - （e_e））） -  1）+（yp * Math.Exp（ - （ e_e））* EXP1））; 
} 
 
  public   static   double  Yt（ double  ypParam）
 {
  return  Xp * B * P * miuk *（ 1   -  Math.Exp（ - （e_e）））+（ypParam *（Math.Exp（ - （e_e）） ））; 
} 
 
  public   static   double  Exp（ double  rtime， double  ypParam）
 {
  return  Math.Exp（ - （Q * F  -  Yt（ypParam））* Lamda）* rtime; 
  //  你真的打算将Yt应用于ypParam，因为ypParam IS本身是Yt（yp） ？ 
  //  即，这是Yt（Yt（yp）） 
} 

一般来说，大量使用 out （和/或 ref ）参数，以及大量静态字段（变量）是代码所示的标志在实施之前没有想到！ （a.k.a.，代码味道）

I have this error in a code I am writing to use method to carry out a formula with an initial value
like

public static double miuk;
        public static double yp = 0;
        private static double e_e = Exp(ref time,out Yt(out yp));//error
        private static double N1, N2, N3, N4, C1, C2, C3, C4;
        private static double Exp1 = Summation(ref N1, ref C1, ref N2, ref C2, ref N3, ref C3, ref N4, ref C4);

        public static double SN(ref double miuK,out double yp )
        {
            yp = 0;
            //yp = Yt(ref miuK,out yp);
            return Xp*B*P*((miuK*(1-Math.Exp(-(e_e)))-1)+(yp*Math.Exp(-(e_e))*Exp1));
            
        }

        public static double Yt(out double yp)
        {
            yp = 0;
            return Xp*B*P*miuk*(1 - Math.Exp(-(e_e))) + (yp*(Math.Exp(-(e_e))));
        }

How do I give the new value gotten from the return to "yo" all over again

Any one with useful idea please its urget.

解决方案

private static double e_e = Exp(ref time,out Yt(out yp));//error

You cannot pass the Yt(out yp) call as an out parameter.

An out parameter must be to a variable or field. It must be a writable location.

I don't know how your Exp(..., ...) method is defined.

(Having a name that similar to Math.Exp() is not a good idea, especially since you also are using Math.Exp() in this code!)

Show the Exp(..., ...) method and I can probably help...
It looks like you really don't need so many out parameters all over the place.

[Edit: MTH]
I'm not sure about this since I still cannot tell what you're actually trying to do.
If you want Yt to always operate on the static yp value, and always to update it then maybe something like:

public static double Yt()
{
    yp = Xp*B*P*miuk*(1 - Math.Exp(-(e_e))) + (yp*(Math.Exp(-(e_e))));
    return yp;
}

Otherwise, maybe more like:

public static double miuk;
public static double yp = Yt(0);
private static double e_e = Exp(time, yp);
private static double N1, N2, N3, N4, C1, C2, C3, C4;
private static double Exp1 = Summation(ref N1, ref C1, ref N2, ref C2, ref N3, ref C3, ref N4, ref C4);
 
public static double SN(ref double miuK,out double yp)
{
// fixing this one left as an exercise... ;-)
    yp = 0;
    //yp = Yt(ref miuK,out yp);
    return Xp*B*P*((miuK*(1-Math.Exp(-(e_e)))-1)+(yp*Math.Exp(-(e_e))*Exp1));
}
 
public static double Yt(double ypParam)
{
    return Xp*B*P*miuk*(1 - Math.Exp(-(e_e))) + (ypParam*(Math.Exp(-(e_e))));
}

public static double Exp(double rtime, double ypParam)
{
  return Math.Exp(-(Q*F - Yt(ypParam))*Lamda)*rtime;
  // did you really intend to apply Yt to the ypParam here since the ypParam IS itself Yt(yp)?
  // I.e., this is Yt(Yt(yp))
}

As a general rule, lots of use of out (and/or ref) parameters, and lots of static fields (variables) is a sign that the code was not thought out before implementing! (a.k.a., "code smell")

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