通用最小方法 [英] Generic minimum method

问题描述

我有一个通用列表，其中包含许多行：

Client.add（新客户端（名称，地址，电话........，a数量））;

我有大约100个这些我想取数字的值并看到它的最小值

I have a generic list with many lines like that :
Client.add (new client ( "name" , "adress","phone " ........ , a number ));
I have about 100 of these i want to take the value of the number and see the minimum value of it

推荐答案

使用LINQ Min方法。

Use LINQ Min method.

var a  = new dynamic[] {new {a ="a", n = 10},new {a ="b", n = 5},new {a ="c", n = 6},new {a ="d", n = 2}};
int min = a.Min(x => x.n);
Console.Write(min);

int min = Client.Min(client => client.a_number);

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