如何以5位存储8位存储数据 [英] How Can I Send Data Stored In 8 Bits In 5 Bits

问题描述

现在数据以8位的形式串行传输现在我想以50位的速度发送5位

Presently data is going serially in the form of 8 bits now i want to send it on 5 bits on 50 bps

推荐答案

这很复杂：如果你的意思是你想要将每个字符5位作为文本类型数据发送，然后使用 Base64 [ ^ ] - 根据您的框架，有多种方法可以转换为/从base64：< br $> b $ b

Google：Base64 [ ^ ]

如果你使用.NET框架，那么这些是可用的：

Convert.ToBase64 [ ^ ]

Convert.FromBase64 [ ^ ]

That's complicated: if you mean you want to send 5 bits per character as text-type data, then look at using Base64[^] - depending on what your framework is, there are various ways to convert to / from base64:

Google: Base64[^]
If you apop uses the .NET framework, then these are available:
Convert.ToBase64[^]
Convert.FromBase64[^]

正如Griff所说，请遵循Base64的原则。请注意，这是一种将8位字符数组转换为6位字符数组的方法，因此您必须实现自己的解决方案以转换为5位字符。



简单地说，你取五个8位字符，将它们放在一个足够长的整数中（例如至少40位，实际上意味着一个64位整数）并在一个读出5位时间，形成8个5位字符。另一方面，你颠倒了这个过程。



现在，关于如何以50 bps传输5位字符，这完全取决于操作系统，以及串行硬件。各种UART和其他通信芯片的接受程度有限。

As Griff says, go for the principle of Base64. Note that this is a method for transposing an array of 8-bit characters into an array of 6-bit characters, so you will have to implement your own solution to transpose into 5-bit characters.

Simply put, you take five 8-bit characters, put them together in one integer of sufficient length (e.g. at least 40 bits, which effectively means a 64-bit integer) and read out five bits at a time, to form eight 5-bit characters. On the other end, you reverse the process.

Now, as for how to transfer 5-bit characters at 50 bps, that depends entirely on the operating system, and the serial hardware. There are limitations in what various UARTs and other communication chips accept.

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