我如何从其进程名称获取窗口标题？ [英] How Could I Get the Window Title from Its Process Name?

问题描述

这是我的代码，用于检查进程名称是否存在：

This is my code to check if the process name existed or not:

bool isRunning (LPCSTR processname)
{
    HANDLE Snapshot;
    Snapshot = CreateToolhelp32Snapshot(TH32CS_SNAPPROCESS, 0);

    if(Snapshot != INVALID_HANDLE_VALUE)
    {
        PROCESSENTRY32 ProcessEntry;
        BOOL           Succeed;
        ProcessEntry.dwSize = sizeof(PROCESSENTRY32);
        Succeed = Process32First(Snapshot, &ProcessEntry);

        while(Succeed)
        {
          if(lstrcmp(ProcessEntry.szExeFile,processname) == 0)
          {
           return true;
          }
      Succeed = Process32Next(Snapshot, &ProcessEntry);
    }

    CloseHandle(Snapshot);
    }
}

如何使用它或编辑它以从其进程名称获取窗口标题（例如notepad.exe）？如果它存在，程序将返回新文本文档 - 记事本之类的文本...我怎么能这样做？

How could I use it or edit it to get the window title from its process name (for example "notepad.exe")? If it existed the program would return text like "New text document - Notepad" ... How could I do so ?

推荐答案

你打电话给 EnumWindows 遍历所有顶级窗口，然后获取每个顶级窗口的进程ID以查看它是否相同。



参见< a href =http://stackoverflow.com/questions/1888863/how-to-get-main-window-handle-from-process-id>此Stack Overflow问题 [ ^ ]，作为google搜索时的第一个结果进程窗口句柄。

You call EnumWindows to go through all top-level windows, and then get the process id for each to see if it's the same.

See this Stack Overflow question[^], found as the first result when googling "window handle from process".

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