在给出示例的getpackagefullname msdn中有错误 [英] having error in getpackagefullname msdn given example

问题描述

如果条件argc值为1，每当我进行调试但控制不进行循环条件时。



示例链接：

http://msdn.microsoft.com/en- us / library / windows / desktop / hh446605（v = vs.85）.aspx [ ^ ]

In if condition argc value will be 1 whenever i do debug but control is not going for loop condition.

example link:
http://msdn.microsoft.com/en-us/library/windows/desktop/hh446605(v=vs.85).aspx[^]

推荐答案

你已经在面对Getpackagefullname API（MSDN）中的错误87 [ ^ ]。请不要重新发布，如果您有其他信息，请编辑原始问题。



你可以从提供我反复要求你的信息开始。

You already asked this question at Facing error 87 in Getpackagefullname API (MSDN)[^]. Please do not repost, if you have additional information then please edit your original question.

You could start by providing the information that I repeatedly asked you for.

我想你参考这部分内容示例代码：

I think you refer to this part of the example code:

if (argc <= 1)
    return ShowUsage();
for (int i=1; i<argc;>

如果你知道C主函数参数的含义，你就不会问这个问题。 argc 是在命令行上传递的参数数量，在 argv 中提供，其中第一个参数 argv [0] 是程序的名称（如果已知）或空字符串。所以 argc 将始终至少为1.



如果你希望 argc 大于1那么做什么 ShowUsage 打印出来：

传递一个或多个附加命令行参数（示例程序的PID编号）。

If you would know the meaning of the C main function arguments, you would not ask this question. argc is the number of arguments passed on the command line and provided in argv where the first argument argv[0] is the name of the program if known or an empty string. So argc will be always at least 1.

If you want argc to be greater than 1 do what ShowUsage prints out:
Pass one or more additional command line arguments (PID numbers for the example program).

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