我怎样才能减少用电量在基于位置的Andr​​oid应用程序？ [英] How can I reduce power usage in a location-based Android application?

问题描述

我怎样才能减少我的应用程序的电源使用情况？什么code，我可以用它来实现这一点？

How can I reduce the power usage in my application? What code can I use to implement this?

推荐答案

有几个不同的方式试图获得位置信息时减少所使用的电源。

There are a couple different ways to reduce the power used when trying to get location information.

1. 使用的<一个href="http://developer.android.com/reference/android/location/LocationManager.html#getLastKnownLocation%28java.lang.String%29">last已知地点而不是试图确定当前位置。

1. Use the last known location instead of trying to determine the current location.

// Get a Location Manager
LocationManager lm = (LocationManager) getSystemService(Context.LOCATION_SERVICE);


// Try to get the last GPS based location
Location l = lm.getLastKnownLocation(LocationManager.GPS_PROVIDER);


// Fall back to cell tower based location if no prior GPS location
if (l == null) {
    l = lm.getLastKnownLocation(LocationManager.NETWORK_PROVIDER);
}

使用更便宜的位置提供。你可以挑选<一个href="http://developer.android.com/reference/android/location/LocationManager.html#NETWORK_PROVIDER">LocationManager.NETWORK_PROVIDER直接或指定你关心的标准，让Android的告诉你使用哪个位置提供。

Use a less expensive location provider. You can pick LocationManager.NETWORK_PROVIDER directly or specify the criteria you care about and let Android tell you which location provider to use.

// Select the criteria you care about
Criteria c = new Criteria();
c.setAccuracy(Criteria.ACCURACY_COARSE);
c.setPowerRequirement(Criteria.POWER_LOW);


// Let the system tell you what provider you should use for your criteria
LocationManager lm = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
String p = lm.getBestProvider(c, true);


// Call other Location Manager functions using the above provider...

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