需要将asp.net c＃验证代码转换为客户端验证（jquery或javascript） [英] Need to convert a asp.net c# validation code into clientside Validation(either jquery or javascript)

问题描述

public static bool ValidateDigit(string sTrn)
   {
       if (sTrn != "")
       {
           if (sTrn.Length < 9) return false;
           //this function multiplies digits 1,4,7 by 3, digits 2,5,8 by 7, and 3,6,9 by 1, and
           //adds the results together. If the total is evenly divisible by 10, then the check digit is ok
           //otherwise, it is not.  example "good" trn = 263181368

           int[] multipliers = new int[3] { 3, 7, 1 };  //multiply each digit by one of these numbers
           int s = 0;
           int m = 0;

           for (int i = 0; i < 9; i++)
           {
               s += int.Parse(sTrn.Substring(i, 1)) * multipliers[m];
               m = ++m < 3 ? m : 0;  //reset to first multiplier
           }

           return (s != 0 && s % 10 == 0) ? true : false;
       }
       else
           return false;
   }

推荐答案

嗨sharonjoy，



这里我根据你的逻辑创建了一个jQuery方法，请查看： -

Hi sharonjoy,

Here I have created one jQuery method as per your logic, please check this out :-

function ValidateNumber(strNo) {
            if (strNo == '' || strNo.length < 9) return false;

            var b = false;
            var s = 0;
            var m = 0;
            var multipliers = [3, 7, 1];

.each（strNo， function （i，n）{
if （n == 1 || n = = 4 || n == 7 ）s + =（n * 3 ）;
如果（n == 2 || n == 5 || n == 8 ）s + =（n * 7 ）;
如果（n == 3 || n == 6 || n == 9 ）s + =（n * 1 ）;
}）;
b =（s！= 0 && s％ 10 == 0 ）？ true ： false ;

return b;
}

.each(strNo, function (i, n) { if (n == 1 || n == 4 || n == 7) s += (n * 3); if (n == 2 || n == 5 || n == 8) s += (n * 7); if (n == 3 || n == 6 || n == 9) s += (n * 1); }); b = (s != 0 && s % 10 == 0) ? true : false; return b; }

希望这对您有所帮助。

Hope this will definitely of help to you.

var x = new Array(3, 7, 1);
       var s = 0;
       var m = 0;
       var j = 0;
       for (i = 0; i < 9; i++) {

           if (m == 0)
               j = 3;
           else if (m == 1)
               j = 7;
           else if (m == 2)
               j = 1;

           s += parseInt(vNumbr[i], 10) * j;

           m = ++m;

           if (m >= 3) {
               m = 0
           }

       }
       return (s != 0 && s % 10 == 0) ? true : false;

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