PopUp div没有使用Javascript函数显示(JavaScript运行时错误:无法获取未定义或空引用的属性'样式') [英] PopUp div is not displaying by using Javascript function (JavaScript runtime error: Unable to get property 'style' of undefined or null reference)
问题描述
使用Javascript函数不显示PopUp div
----------------------- -------------------------------------
Js函数
-------------------
PopUp div is not displaying by using Javascript function
------------------------------------------------------------
Js function
-------------------
function btnExportLE_click() {
debugger;
document.getElementById('<%=dvladen.ClientID %>').style.display = "block";
document.getElementById('<%=dvHider.ClientID %>').style.display = "block";
return false;
}
风格
-----
Style
-----
.dvladen
{
z-index: 2;
position: absolute;
width: 599px;
height: 398px;
border-width: 0px;
top: 280px;
left: 573px;
background-color: White;
}
DIV
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DIV
--------
<div id="dvladen" runat="server" class="popup" visible="false" >
<p> HAIII</p>
</div>
<div id="dvHider" runat="server" class="hider">
</div>
然后我在Button Click中调用了Js函数/>
< asp:Button ID =btnExportLErunat =serverclass =btnNewText =Export LE
OnClientClick = return btnExportLE_click(); />
PAge Load
----------
dvladen.Style [display] =none;
但它显示的错误如
JavaScript运行时错误:无法获取未定义或空引用的属性样式
请帮我解决这个问题..
问候
Jithesh
Then I called Js function in Button Click
<asp:Button ID="btnExportLE" runat="server" class="btnNew" Text="Export LE"
OnClientClick="return btnExportLE_click();" />
PAge Load
----------
dvladen.Style["display"] = "none";
But It Showing An error like
JavaScript runtime error: Unable to get property 'style' of undefined or null reference
please help me to solve this..
Regards
Jithesh
推荐答案
请检查document.getElementById('<%= dvladen.ClientID%>')是否为null。这就是风格无法识别的原因。如果您没有使用母版页,那么您可以简单地使用没有客户端ID的控件ID。
Please check document.getElementById('<%=dvladen.ClientID %>') is throwing null. That's why style is not recognize . if you are not using master page then you can simply use Id of control without client Id.
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