如何使用c＃创建xml [英] How to create xml using c#

问题描述

i想要像这样创建XML

 <  记录 >  
 <   FIELD     ID   =  1  MAX_LENGTH   =  100    /  >  
  <   FIELD     ID   =  2    MAX_LE NGTH   =  100    /  >  
 <   FIELD     ID   =  3    MAX_LENGTH   =  7  /  >  
 <   FIELD     ID   =  4    MAX_LENGTH   =  100  /   >  
 <   FIELD     ID   =  5    MAX_LENGTH   =  100  /  >  
 <   / RECORD  >  
 <   ROW  >  
 <   COLUMN     SOURCE   =  3    NAME   =  Col1    /  >  
 <   COLUMN     SOURCE   =  2    NAME   =  Col2    /  >  
 <   COLUMN     SOURCE   =  1    NAME   =  Col3    /  >  
 <   COLUMN     SOURCE   =  4    NAME   =  Col4    /  >  
 <   / ROW  > ;  

这是我到目前为止所做的，但它在最后一行中的抛出错误为此文档已经有一个documentelement节点

 XmlDocument xmlDoc =  new  XmlDocument（）; 
 XmlElement rootNode = xmlDoc.CreateElement（  RECORD）; 
 xmlDoc.AppendChild（rootNode）; 
 
  int  dbIndex =  0 ; 
  foreach （ColumnMapping columnMapping  in  columnMappings）
 {
 XmlNode userNode = xmlDoc.CreateElement（  FIELD）; 
 XmlAttribute attribute = xmlDoc.CreateAttribute（  ID）; 
 attribute.Value = dbIndex.ToString（）; 
 userNode.Attributes.Append（attribute）; 
 rootNode.AppendChild（userNode）; 
 dbIndex ++; 
} 
 
 rootNode =  null ; 
 rootNode = xmlDoc.CreateElement（  ROW）; 
 xmlDoc.AppendChild（rootNode）; 
 

解决方案

XmlDocument不允许这样做 - 它一次只能支持一个文档。您在顶部显示的示例是两个文档。将它们组合成一个文档（带有一个根节点），或者单独生成它们。







XML文档形成一个从根开始并分支到叶​​子的树结构。



XML文档必须包含一个根元素。这个元素是所有其他元素的父级。



XML文档中的元素构成一个文档树。树从根开始并分支到树的最低层。



- http：//www.w3schools。 com / xml / xml_tree.asp [ ^ ]

您可以使用 XmlSerializer ， XDocument 或 XmlWriter



阅读这个主题以获取更多细节。它解释得非常好在c中创建xml＃



也可以阅读 C＃XmlWriter

 XmlDocument xmlDoc =  new  XmlDocument（）; 
 xmlDoc.AppendChild（xmlDoc.CreateElement（  TABLE））;  //   DocumentElement  
 XmlElement rootNode = xmlDoc.CreateElement（  RECORD）; 
 xmlDoc.DocumentElement.AppendChild（rootNode）;  //   DocumentElement  
 
  int  dbIndex =  0 ; 
  foreach （ColumnMapping columnMapping  in  columnMappings）
 {
 XmlNode userNode = xmlDoc.CreateElement（  FIELD）; 
 XmlAttribute attribute = xmlDoc.CreateAttribute（  ID）; 
 attribute.Value = dbIndex.ToString（）; 
 userNode.Attributes.Append（attribute）; 
 rootNode.AppendChild（userNode）; 
 dbIndex ++; 
} 
 
 rootNode =  null ;  //  不用 
 rootNode = xmlDoc.CreateElement（  ROW）; 
 xmlDoc.DocumentElement.AppendChild（rootNode）;  //   DocumentElement  
 

hi,

i want to create XML like this

<RECORD>
  <FIELD ID="1"MAX_LENGTH="100" />
  <FIELD ID="2" MAX_LENGTH="100" />
  <FIELD ID="3" MAX_LENGTH="7"/>
  <FIELD ID="4" MAX_LENGTH="100"/>
  <FIELD ID="5" MAX_LENGTH="100"/>
 </RECORD>
 <ROW>
  <COLUMN SOURCE="3" NAME="Col1" />
  <COLUMN SOURCE="2" NAME="Col2" />
  <COLUMN SOURCE="1" NAME="Col3" />
  <COLUMN SOURCE="4" NAME="Col4" />
 </ROW>

This is what i have done so far, but its throwing error in the last line as "This document already has a documentelement node"

XmlDocument xmlDoc = new XmlDocument();
XmlElement rootNode = xmlDoc.CreateElement("RECORD");
xmlDoc.AppendChild(rootNode);

int dbIndex = 0;
foreach (ColumnMapping columnMapping in columnMappings)
{
  XmlNode userNode = xmlDoc.CreateElement("FIELD");
  XmlAttribute attribute = xmlDoc.CreateAttribute("ID");
  attribute.Value = dbIndex.ToString();
  userNode.Attributes.Append(attribute);
  rootNode.AppendChild(userNode);
  dbIndex++;
}

rootNode = null;
rootNode = xmlDoc.CreateElement("ROW");
xmlDoc.AppendChild(rootNode);

解决方案

XmlDocument won't allow that -- it can only support one document at a time. The example you show at the top is two documents. Either combine them into one document (with one root node), or produce them separately.


"
XML documents form a tree structure that starts at "the root" and branches to "the leaves".

XML documents must contain a root element. This element is "the parent" of all other elements.

The elements in an XML document form a document tree. The tree starts at the root and branches to the lowest level of the tree.
"
-- http://www.w3schools.com/xml/xml_tree.asp[^]

You can use XmlSerializer , XDocument or XmlWriter

Read this thread for more details.It explains very well about creating xml in c#

Read C# XmlWriter too

XmlDocument xmlDoc = new XmlDocument();
xmlDoc.AppendChild(xmlDoc.CreateElement("TABLE"));  // DocumentElement
XmlElement rootNode = xmlDoc.CreateElement("RECORD");
xmlDoc.DocumentElement.AppendChild(rootNode);       // DocumentElement

int dbIndex = 0;
foreach (ColumnMapping columnMapping in columnMappings)
{
  XmlNode userNode = xmlDoc.CreateElement("FIELD");
  XmlAttribute attribute = xmlDoc.CreateAttribute("ID");
  attribute.Value = dbIndex.ToString();
  userNode.Attributes.Append(attribute);
  rootNode.AppendChild(userNode);
  dbIndex++;
}

rootNode = null;                                // needless
rootNode = xmlDoc.CreateElement("ROW");
xmlDoc.DocumentElement.AppendChild(rootNode);   // DocumentElement

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