C＃中的三角形打印数字 [英] Print Numbers In triangle Form in C#

问题描述

我想打印这样的数字



1

212

32123

4321234

543212345

4321234

32123

132

1





但是没有进入三角形最后1 ...我的代码是

I want to Print Numbers Like This

1
212
32123
4321234
543212345
4321234
32123
212
1


But Not Getting Under The Triangle Last 1...My Code Is

static void Main(string[] args)
       {
           for (int i = 1; i <= 5; i++)
           {

               for (int j = i; j > 1; j--)
               {
                   Console.Write(j +" ");
               }
               for (int k = 1; k <= i; k++)
               {
                   Console.Write(k+" ");
               }
              Console.WriteLine();
           }

           for (int k = 4; k > 1; k--)
           {
               for (int l = k; l > 1; l--)
               {
                   Console.Write(l+" ");
               }
               for (int n = 1; n <= k; n++)
               {
                   Console.Write(n+" ");
               }
               Console.WriteLine();
           }
       }

推荐答案

引用：

for（int k = 4; k> 1; k - ）

for (int k = 4; k > 1; k--)

应该是

Should be

for (int k = 4; k >= 1; k--)

而循环是此任务的更好选择。

while loops are a better choice for this task.

int y = 0 ;
while ( y < 5 ) F ( ++y ) ; 
while ( y > 1 ) F ( --y ) ;

private static void F ( int x )
{
//    int y = 0 ;
//    while ( y < x ) System.Console.Write ( ++y ) ; 
//    while ( y > 1 ) System.Console.Write ( --y ) ;

    int y = x + 1 ;
    while ( y > 1 ) System.Console.Write ( --y ) ;
    while ( y < x ) System.Console.Write ( ++y ) ; 

    System.Console.WriteLine() ;
}

现在加油！

你有代码打印上半部分：使用forloop在控制台应用程序中进行打印 [ ^ ]所以你要做的就是在底部添加另一组以反转它！



就个人而言，我转换了我必须使用的方法来打印线：将内部两个循环移动到方法中并调用它，传递 i 通过。

然后添加另一个循环以反向我，再次调用它！

Now come on!
You have the code to print the top half: print in console application by using forloop[^] so all you have to do is add another set at the bottom to reverse it!

Personally, I'd convert what I had to use a method that prints the line: move the inner two loops into the method and call it, passing i through.
Then add another loop to "reverse" i, and call it again!

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