如何将其转换为伪代码 [英] How Do I Can Convert It Into Pseudocode

问题描述

  #include   <   iostream  >  
   #include   <   math.h  >  
   #include   <   iomanip  >  
  使用 命名空间标准; 
 
  int  main（）
 {
  int  Geometry_Calculator，Calculate_the_Area_of_a_Rectangle，宽度，长度，退出，选择; 
  double  Calculate_the_Area_of_a_Triangle，base，height; 
  float  Calculate_the_Area_of_a_Circle，radius; 
 
 cout<<   Geometry_Calculator<< endl; 
 cout<<   1.Calculate_the_Area_of_a_Circle<< endl; 
 cout<<   2.Calculate_the_Area_of_a_Rectangle<< endl; 
 cout<<   3.Calculate_the_Area_of_a_Triangle<< endl; 
 cout<<   4.Quit<< endl; 
 cout<<   Enter_your_choice（1-4）：<< endl ; 
 cin>> choice; 
 
 开关（选择）
 {
 
  case   1 ：cout<< fixed<< showpoint; 
 cout<< setprecision（ 2 ）; 
 cout<<  输入radius：; 
 cin>> radius; 
 Calculate_the_Area_of_a_Circle =  3 。 14159  *（pow（radius， 2 ））; 
 cout<<   Total_Area_of_a_Cirlce：<<< Calculate_the_Area_of_a_Circle<< endl; 
  break ; 
  case   2 ：cout<<   输入宽度：; 
 cin>> width; 
 cout<<  输入长度：; 
 cin>>长度; 
 Calculate_the_Area_of_a_Rectangle = width * length; 
 cout<<   Total_Area_of_a_Rectangle：<<< Calculate_the_Area_of_a_Rectangle<< endl; 
  break ; 
  case   3 ：cout<<   输入base：; 
 cin>> base; 
 cout<<  输入高度：; 
 cin>> height; 
 Calculate_the_Area_of_a_Triangle =  0 。 5  *（base * height）; 
 cout<<   Total_Area_of_a_Triangle：<<< Calculate_the_Area_of_a_Triangle<< endl; 
  break ; 
  case   4 ：cout<<   退出<< endl; 
  break ; 
 
 默认：cout<<  输入错误。请再试一次。<< endl; 
} 
 
 system（  pause）; 
  return   0 ; 
 
} 

解决方案

没有这样的标准伪代码，所以没有一种方法可以转换它。伪代码不仅仅是人类可读格式的编程结构，而不是实际的编程语言 - 所以如果你的教师/工作场所没有关于伪代码格式的限制，你可以在你的路上做，只要它可以理解它会好的！ （它也可以是非英语！）



http：/ /en.wikipedia.org/wiki/Pseudocode [ ^ ]

http://www.unf.edu/~broggio/cop2221/ 2221pse.htm [ ^ ]

#include<iostream>
#include<math.h>
#include<iomanip>
using namespace std;

int main ()
{
    int Geometry_Calculator,Calculate_the_Area_of_a_Rectangle,width,length,Quit,choice;
    double Calculate_the_Area_of_a_Triangle,base,height;
    float Calculate_the_Area_of_a_Circle,radius;
    
    cout<<"Geometry_Calculator"<<endl;
    cout<<"1.Calculate_the_Area_of_a_Circle"<<endl;
    cout<<"2.Calculate_the_Area_of_a_Rectangle"<<endl;
    cout<<"3.Calculate_the_Area_of_a_Triangle"<<endl;
    cout<<"4.Quit"<<endl;
    cout<<"Enter_your_choice (1-4):"<<endl;
    cin>>choice;
    
    switch (choice)
    {
           
      case 1:cout<<fixed<<showpoint;
            cout<<setprecision (2); 
            cout<<"Enter radius:";
            cin>>radius;
            Calculate_the_Area_of_a_Circle=3.14159*(pow(radius,2));
            cout<<"Total_Area_of_a_Cirlce:"<<Calculate_the_Area_of_a_Circle<<endl;
            break;
      case 2:cout<<"Enter width:";
             cin>>width;
             cout<<"Enter length:";  
             cin>>length; 
             Calculate_the_Area_of_a_Rectangle=width*length;
             cout<<"Total_Area_of_a_Rectangle:"<<Calculate_the_Area_of_a_Rectangle<<endl;
         break;
      case 3:cout<<"Enter base:";
             cin>>base;
             cout<<"Enter height:";
             cin>>height;
             Calculate_the_Area_of_a_Triangle=0.5*(base*height);
             cout<<"Total_Area_of_a_Triangle:"<<Calculate_the_Area_of_a_Triangle<<endl;
         break;
      case 4:cout<<"Quit"<<endl;
         break;
      
      default:cout<<"Wrong input.Please try again."<<endl;
    }   
    
    system ("pause");
    return 0;
                
}

解决方案

There is no such a thing standard pseudo code, so there is no one way to convert it. Pseudo code is not more than a programming structure in human readable format rather than in actual programming language - so if you have no restrictions from your teacher/working place about pseudo code format you can do it on your way and as long as it understandable it will be all right! (And it can be non-English too!)

http://en.wikipedia.org/wiki/Pseudocode[^]
http://www.unf.edu/~broggio/cop2221/2221pseu.htm[^]

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