根据选择填充下拉列表 [英] Populate dropdownlist based on selection
本文介绍了根据选择填充下拉列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
$("#year1").change(function(){
var dataString = $(this).val();
$.ajax({
type: "POST",
url:"Servlet",
dataType: "json",
data: {
year :JSON.stringify(dataString)
},
success: function(result) {
console.log(result);
$('#category1').multipleSelect({
filter: true,
selectAll: false
});
}
});
return false;
});
//servlet
response.setContentType("text/html;charset=UTF-8");
PrintWriter out = response.getWriter();
String[] year = request.getParameterValues("year1"); //error
//现在我的代码基于id year1下拉列表,将出现category1下拉列表,但我在该行有空指针。
//Hi now my code is based on the id year1 dropdown value, the category1 dropdownlist will appear, but i got null pointer at that line.
推荐答案
( #year1)。change(function(){
var dataString =
("#year1").change(function(){ var dataString =
( this )。val();
.ajax({
type: POST,
url: Servlet,
dataType: json,
data:{
year:JSON.stringify(dataString)
},
成功:函数(结果){
console.log(result);
.ajax({ type: "POST", url:"Servlet", dataType: "json", data: { year :JSON.stringify(dataString) }, success: function(result) { console.log(result);
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