如何在java中打开局部视图“window.open（）” [英] How to Open a Partial View in java "window.open()"

问题描述

嗨



i想在window.open（）java脚本方法中打开局部视图



like：window.open（'/ docs / Calculator / Calculator.html'，PopupWindow，'width = 500px，height = 500px，top = 150，left = 250'）;



怎么可能请帮我

hi

i want to open a partial view in window.open() java script method

like: window.open('/docs/Calculator/Calculator.html', "PopupWindow", 'width=500px,height=500px,top=150,left=250');

how it possible pls help me

推荐答案

创建一个控制器或者你可能已经创建了

create a controller or you may be you have already created as

public PartialViewResult ShowPopup()
        {
            return PartialView();

        }

ShowPopup是你的页面名称。



传递网址为

ShowPopup is yor page name.

pass url as

window.open('@Url.Action("ShowPopup", "PopupController")', "PopupWindow", 'width=500px,height=500px,top=150,left=250');

我解决了它



window.open（'@ ​​Url.Action （ActionName，ControllerName）'，PopupWindow，width = 500px，height = 500px，top = 150，left = 250'）;

I solve it

window.open('@Url.Action("ActionName", "ControllerName")', "PopupWindow", 'width=500px,height=500px,top=150,left=250');

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