在'{'标记之前的预期表达式 [英] expected expression before ‘{’ token

问题描述

我在编译后发现了他的错误。我找不到错误，请问是什么错误？

错误：

错误：预期表达式在'{'标记之前

item [0 ] = {rice，10,40,30};

Hi, I gott his error after compiling. I could not find the error, whats the error please?
error:
error: expected expression before ‘{’ token
item[0]={"rice",10,40,30};

#include<stdio.h>
#include<stdlib.h>
#define ITEMLIMIT 7
#define NOOFITEM  3

struct item_info
{
      char itemname[15];
      int quantity;
      float retail;
      float wholesale;
      //int quatityonorder;
 }item[NOOFITEM];

int main()
{
       item[0]={"rice",10,40,30};
       // item[1]={"sugar",10,40,30};
       // item[2]={"soap",10,40,30};
      int choice = 0,i=0,quantity=0;
      char *itemname;
      printf("item name\t quantity\t retailsprice\t wholesaeprice\t");

     for(i=0;i<NOOFITEM;i++)
          {
          printf("%s\t %d\t %f\t %f\t",item[i].itemname,item[i].quantity,item[i].retail,item[i].wholesale);
           }

    printf("enter the item which u want\n");
        scanf("%[^\n]s",itemname);

     for(i=0;i<NOOFITEM;i++)
        {
            if(strcmp(item[i].itemname,itemname)==0);
      {
                   printf("%s is %d the item in our stock",itemname,i);
        }

        puts("*** checking for item availabiity ****");
        if(item[i].quantity<0)
     {

         puts("item is out of stock");
     }

         else if(item[i].quantity>0)
         {
             printf("quantity of %s avalable is %d",itemname,item[i].quantity);
         }

    printf("enter quatity you want");
    scanf("%d", &quantity);
     if("item[i].quantity>=ITEMLIMIT")
 
<pre lang="cs">printf("your should pay %f as wholesale price",item[i].wholesale*item[i].quantity);
    }

     else if(item[i].quantity< ITEMLIMIT)
    {
           printf("your should pay %f as retail price",item[i].retail*item[i].quantity);
            item[i].quantity=item[i].quantity-quantity;
    }

    printf("enter 2 to coninue");
    scanf("%d",&choice);

    if(choice==1)

<pre lang="cs">break;
    else if(choice==2)
        continue;
}
}

推荐答案

您无法在运行时初始化类似的结构。如果你使用常量值，那么你可以让编译器通过编码来设置它：

You cannot initialise a structure like that at run time. If you are using constant values then you can get the compiler to set it up by coding:

struct item_info
{
      char itemname[15];
      int quantity;
      float retail;
      float wholesale;
      //int quatityonorder;
}item[NOOFITEM] =
{
    {"rice",10,40,30},
    {"sugar",10,40,30},
    {"soap",10,40,30}
};

但是如果要在运行时分配值，则必须手动执行以下操作：

But if you want to assign values at run time then you have to do it manually like:

strcpy(item[0].itemname, "rice");
item[0].quantity = 10;
item[0].retail = 40;
item[0].wholesale = 30;

如果你改变它所以它应该编译，但它不是最好的方式

if you change it so it should compile, but it is not the best way

struct item_info
{
      char *itemname;
      int quantity;
...

你遇到的问题是itemname只是一个指针，你需要分配并释放它。并以某种方式管理它。



我会写一个Setter

You have than the problem that itemname is only a pointer and you need to alloc and free it. And manage it somehow.

I would write an "Setter"

Set(struct *item_info, char*name, ...)
{
 strncpy( item_info->name, sizeof(item_info->name), name);//check length!!!

...
}

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