JavaScript的Google Analytics控制台日期格式错误 [英] Google Analytics Dashboard Date Format Error With JavaScript

问题描述

我正在创建Google Analytics信息中心。在那里开始日期&使用JQuery日期选择器插入结束日期。我以mm / dd / yyyy格式插入日期。但我想在yyyy-mm-dd中提交它们。我使用以下代码来做到这一点。

I'm creating a Google Analytics Dashboard. In there the Start Date & End Date is inserted using JQuery Date Picker. I am inserting dates in the mm/dd/yyyy format. But I want to submit them in the yyyy-mm-dd. I have used the following code to do that.

$("#to_date, #from_date").datepicker({maxDate: new Date(),dateFormat:'yyyy-mm-dd'});

在那里插入的日期为20142014-07-01而不是2014-07-01。所以我将格式更改为yy-mm-dd。之后我在提交此日期后收到错误说



** {error：{errors：[{domain： global，reason：invalidParameter，message：无效的值'2014-07-24'。值必须与以下正则表达式匹配：'[0-9] {4} - [0-9] {2} - [0-9] {2} |今天|昨天| [0-9] +（daysAgo）' ，locationType：参数，location：end-date}，{domain：global，reason：invalidParameter，message：无效值2014-07- 01'。值必须与以下正则表达式匹配：'[0-9] {4} - [0-9] {2} - [0-9] {2} |今天|昨天| [0-9] +（daysAgo）' ，locationType：参数，位置：开始日期}，代码：400，消息：无效值'2014-07-24'。值必须与以下正则表达式匹配：'[0-9] {4} - [0-9] {2} - [0-9] {2} |今天|昨天| [0-9] +（daysAgo）' }} **



我使用的是JavaScript。



我无法理解我该怎么办。谁能告诉我怎么做？



Thnaks&问候，

Chiranthaka

At there the date inserted as 20142014-07-01 not as 2014-07-01. So I changed the format to yy-mm-dd. After that I got an error when after submit this date saying

" **{"error":{"errors":[{"domain":"global","reason":"invalidParameter","message":"Invalid value ' 2014-07-24 '. Values must match the following regular expression: '[0-9]{4}-[0-9]{2}-[0-9]{2}|today|yesterday|[0-9]+(daysAgo)'","locationType":"parameter","location":"end-date"},{"domain":"global","reason":"invalidParameter","message":"Invalid value ' 2014-07-01 '. Values must match the following regular expression: '[0-9]{4}-[0-9]{2}-[0-9]{2}|today|yesterday|[0-9]+(daysAgo)'","locationType":"parameter","location":"start-date"}],"code":400,"message":"Invalid value ' 2014-07-24 '. Values must match the following regular expression: '[0-9]{4}-[0-9]{2}-[0-9]{2}|today|yesterday|[0-9]+(daysAgo)'"}}** "

I am using JavaScript.

I cannot understand what should I do. Can anyone show me how to do this?

Thnaks & regards,
Chiranthaka

推荐答案

（ ＃to_date，＃from_date）。datepicker（{maxDate： new 日期（），dateFormat：' yyyy-mm-dd'}）;

("#to_date, #from_date").datepicker({maxDate: new Date(),dateFormat:'yyyy-mm-dd'});

在那里插入的日期为20142014-07-01而不是2014-07-01。所以我将格式更改为yy-mm-dd。之后我在提交此日期后收到错误说



** {error：{errors：[{domain： global，reason：invalidParameter，message：无效的值'2014-07-24'。值必须与以下正则表达式匹配：'[0-9] {4} - [0-9] {2} - [0-9] {2} |今天|昨天| [0-9] +（daysAgo）' ，locationType：参数，location：end-date}，{domain：global，reason：invalidParameter，message：无效值2014-07- 01'。值必须与以下正则表达式匹配：'[0-9] {4} - [0-9] {2} - [0-9] {2} |今天|昨天| [0-9] +（daysAgo）' ，locationType：参数，位置：开始日期}，代码：400，消息：无效值'2014-07-24'。值必须与以下正则表达式匹配：'[0-9] {4} - [0-9] {2} - [0-9] {2} |今天|昨天| [0-9] +（daysAgo）' }} **



我使用的是JavaScript。



我无法理解我该怎么办。谁能告诉我怎么做？



Thnaks&问候，

Chiranthaka

At there the date inserted as 20142014-07-01 not as 2014-07-01. So I changed the format to yy-mm-dd. After that I got an error when after submit this date saying

" **{"error":{"errors":[{"domain":"global","reason":"invalidParameter","message":"Invalid value ' 2014-07-24 '. Values must match the following regular expression: '[0-9]{4}-[0-9]{2}-[0-9]{2}|today|yesterday|[0-9]+(daysAgo)'","locationType":"parameter","location":"end-date"},{"domain":"global","reason":"invalidParameter","message":"Invalid value ' 2014-07-01 '. Values must match the following regular expression: '[0-9]{4}-[0-9]{2}-[0-9]{2}|today|yesterday|[0-9]+(daysAgo)'","locationType":"parameter","location":"start-date"}],"code":400,"message":"Invalid value ' 2014-07-24 '. Values must match the following regular expression: '[0-9]{4}-[0-9]{2}-[0-9]{2}|today|yesterday|[0-9]+(daysAgo)'"}}** "

I am using JavaScript.

I cannot understand what should I do. Can anyone show me how to do this?

Thnaks & regards,
Chiranthaka

datepicker 小部件的格式字符串使用 yy 代表四位数年份。通过将格式设置为 yyyy-mm-dd ，您已经告诉它将四位数年份跟随四位数年份，这就是为什么你这么做的原因获取 20142014 。



将日期格式更改为 yy-mm-dd 你应该得到正确的输出。



http://api.jqueryui.com/datepicker/#utility-formatDate [ ^ ]

The format string for the datepicker widget uses yy to represent the four-digit year. By setting the format to yyyy-mm-dd, you've told it to put the four-digit year followed by the four-digit year, which is why you're getting 20142014.

Change the date format to yy-mm-dd and you should get the correct output.

http://api.jqueryui.com/datepicker/#utility-formatDate[^]

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