如何用模式生成字符串？ [英] How to generate strings with pattern?

问题描述

大家好！

我的网站有一个要求会自动生成字符串，如果添加另一条记录则会自动增加5。例如，如果用户将从下拉列表中选择代码，它将自动生成子项代码，如下所示：



PPY-05 ---> ; PPY-CC-05

---> PPY-CC-10

---> PPY-CC-15



顺便说一句，第一个代码（PPY-05）来自名为milestone_code的数据库。因此，如果用户想要创建该milestone_code的子项，则它将是PPY-CC-05，PPY-CC-10等。然后，此子项将保存到名为check_code的数据库中。此check_code还将包含子项。如果用户从下拉列表中选择PPY-CC-05，网站将自动生成如下所示的代码：



PPY-CC-05 - - > PPY-CC-AC-05

---> PPY-CC-AC-10



所有商品代码都应自动添加5.



有人能帮帮我吗？希望你理解我的问题：）

Hi guys!
I have a requirement in my website that would automatically generate strings and automatically increase by 5 if another record will be added. For example,if the user will select a code from a drop down list, it will automatically generate sub items code as shown below:

PPY-05 ---> PPY-CC-05
---> PPY-CC-10
---> PPY-CC-15

By the way, the first code (PPY-05) is taken from the database named milestone_code. So if the user would like to create sub items of that milestone_code, it will be PPY-CC-05, PPY-CC-10 and so on. Then this sub items will be saved into the database named check_code. This check_code will also have sub items. if the user will choose PPY-CC-05 from a drop down list the website will automatically generate their code like this one below:

PPY-CC-05 ---> PPY-CC-AC-05
---> PPY-CC-AC-10

all of the item codes should be added automatically by 5.

Can somebody help me? Hope you understand my problem :)

推荐答案

你好，



你的要求听起来很有趣，但我是不确定你在哪里使用StringBuilder

，你可以很容易地实现这一点，保持数字部分分开，因为你想为每个新的选择增加它，并保持最后的asign数和代码的历史记录不同的变量。



我不确定你是如何使用数据库的，但我希望你能轻松完成。但仍然供你参考，请看这个链接



http://msdn.microsoft.com/en-us/library/2839d5h5(v = vs.110）.aspx [ ^ ]





我希望它能解决你的问题......请评论一下，如果它适用于你：）

Hi,

Your requirement sounds interesting, but i am not sure where are you stuck
using StringBuilder , you can easily achieve this , keep the number part separate as you want to increase it for every new selection , and maintain a history of last asign number and code in different variables.

I am not sure how you are using the Database , but i hope you can do it easily. but still for your reference please see this link

http://msdn.microsoft.com/en-us/library/2839d5h5(v=vs.110).aspx[^]


I hope it solves your problem... please comment if it works for you :)

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