C语言问题。 [英] C Language Question.

问题描述

您好，我刚刚在Microsoft Visual Studio 2010中用C语言编写了一个简单的基本程序。在程序中出现了如下问题。

Hello, I was just writing a simple basic program in C language in Microsoft Visual Studio 2010. There is a problem occurred in it as follows in a program.

//Program showing all the binary operators used in C.

#include "stdafx.h"
#include<stdio.h>
#include<conio.h>

void main()
{
    int x,y,c,d;

    printf("Enter The Value of X and Y :    ");
    scanf("%d %d",&x,&y);
    printf("\n\nThe integers are        %d & %d\n",x,y);
    printf("\nThe Addition gives:-      %d\n",x+y);
    printf("\nThe Subtraction gives:-       %d\n",x-y);
    printf("\nThe Multiplication gives:-    %d\n",x*y);
    printf("\nThe Division gives:-      %d\n",x/y);
    printf("\nThe Modulus gives:-       %d\n",x%y);
    printf("\nThe Increment gives:-     %d  &  %d\n",x++,y++);
    printf("\nThe Decrement gives:-     %d  &  %d\n",x--,y--);

    getch();
}

然后我得到了输出。



输入X和Y的值： 6 5



整数 6& 5

加法给出： - 11

减法给出： - 1

乘法给出： - 30

该司给出： - 1

模数给出： - 1

增量给出： - 6& 5

递减给出： - 7& 6





问题在于递增和递减操作。这是软件故障还是我错过了什么！但我认为在Visual Studio 2010中尝试了一切，但输出不会改变。

Thanx。

Then I got the Output.

Enter The Value of X and Y : 6 5

The integers are 6 & 5
The Addition gives:- 11
The Subtraction gives:- 1
The Multiplication gives:- 30
The Division gives:- 1
The Modulus gives:- 1
The Increment gives:- 6 & 5
The Decrement gives:- 7 & 6


The problem is in Increment and Decrement operation. Is that a software fault or I missed something! But I think tried everything in Visual Studio 2010 but output wont change.
Thanx.

推荐答案

没有问题一点都不这一切都按预期计算。确保你了解 pre - 增量应该做什么，知道预增量和后增量之间的差异。

-SA

There is no a problem at all. It all is calculated as expected. Make sure you understand what a pre-increment should do, know the difference between pre-increment and post-increment.

—SA

不，没错。

No, that's right.

x++

是 后增量 操作 - 它获取值然后将源增加1并使用它开始的值。

所以

is a postincrement operation - it gets the value then increases the source by one and uses teh value it started with.
So

printf("\nThe Increment gives:-     %d  &  %d\n",x++,y++);

相当于：

Is the equivalent of:

printf("\nThe Increment gives:-     %d  &  %d\n",x,y);
x = x + 1;
y = y + 1;

如果您想尝试，请设置 preincrement 运算符：

There is a preincrement operator if you want to try that instead:

printf("\nThe Increment gives:-     %d  &  %d\n",++x,++y);

这相当于：

That is the equivalent of:

x = x + 1;
y = y + 1;
printf("\nThe Increment gives:-     %d  &  %d\n",x,y);

这可能是yopu所期待的。

Which might be what yopu were expecting.

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