RGB值转换为数组 [英] RGB value convert to in array

问题描述

我有一些RGB颜色值，比如＃e03cec，我想把它变成int数组，我需要一些帮助。

我写了这样的代码：

I have some RGB color value like #e03cec and I want to make it to int array ,I need some help.
I have write code like this:

public static int [] TestInt(String rgbColor)
{
    String rgb = rgbColor.substring(1, rgbColor.length());
    String [] Hex= new String [3];
    int [] IntRgb =new int [3];
    for(int i=0;i<3;i++)
    {
      Hex[i]=rgb.substring(2*i,2*i+2);
      IntRgb[i]=Integer.parseInt(Hex[i],16);
    }
    return IntRgb;
}

但是我无法确定它是否正确。

but I can not make sure whether it is right.

推荐答案

它是其实很容易检查。写一个测试:)





所以，你想测试你的方法是否正确地将输入RGB字符串转换为3元素整数数组。



您给出的顺序应分为以下三个元素



R = e0，其中是0xe0

G = 3c，即0x3c

B = ec，即0xec



所以要测试，我会说你使用像 junit 这样的单元测试框架，但下面是一个快速而肮脏的测试片段，用于解释原理。 />

It is actually very easy to check. Write a test :)


So, you want to test if your method correctly converts the input RGB string into a 3 element integer array.

The sequence you gave should be split into the following three elements

R = e0, which is 0xe0
G = 3c, which is 0x3c
B = ec, which is 0xec

So to test, I would sucggest you use a unit testing framework like junit, but below is a quick and dirty test snippet, to explain the principle.

int[] result = TestInt("#e03cec");

// So because it is integer value, you can compare the hex values
// expected to the array
if (result[0] != 0xe0) throw new RuntimeException("Error");
if (result[1] != 0x3c) throw new RuntimeException("Error");
if (result[2] != 0xec) throw new RuntimeException("Error");

// (or if you are really paranoid you can use
// a calculator to convert the hex to base 10 (int) which would be
// 224, 60 and 236
if (result[0] != 224) throw new RuntimeException("Error");
if (result[1] != 60) throw new RuntimeException("Error");
if (result[2] != 236) throw new RuntimeException("Error");

System.out.println("OK");

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