使用零元素/忽略最后一个char时匹配集合的问题 [英] problem with match collection in using zero element/ignoring last char

问题描述

我有很少的用户输入，我试图通过MatchCollection与我有不同的模式进行比较，即

  string  user =   \ b（？：I | would | like |要|见| ID |的|买|好）\b; 
 

但当我匹配字符串

  string  pattern =   ^？。（= * \bgoods？|？项目？|？事\b）（？= * \bbought\b）（= * \bid\b ）（= * \btest\b）* $？。; 
 
 MatchCollection mat = Regex.Matches（pattern，user）; 
 
  foreach （ var  item  in  mat）
 {
 Console.WriteLine（item.ToString（））; 
} 
 

匹配上述两项时，匹配集合只会产生/收集匹配（id，但是忽略了第一块模式中的商品。它似乎无视**？**前瞻提到商品？|物品？|东西？



任何建议。





谢谢

解决方案

;

MatchCollection mat = Regex.Matches（pattern，user）;

foreach （ var item in mat）
{
Console.WriteLine（item.ToString（））;
}

匹配两者上面，匹配集合只产生/收集（id，buy）的匹配但忽略了第一块模式中的货物。它似乎忽略了**？**前瞻提到货物？|物品？|东西？。



任何建议。





谢谢

您好，



将您的表情更改为：

  string  pattern =  （？=。* \\ \\bgoods \b | \bitems\b |？。？。？。\bthings \b）（= * \bbought\b）（= * \bid\b）（= * \ btest \b）。*; 

投入？ '''之后''中的东西？'会捕捉到东西和东西。



你需要在可选列表中的每个单词周围加上单词边界。

（您在用户输入中也拼错了货物为好，但我认为您的意思是货物。 ）

I have few user inputs which I am trying to compare via MatchCollection with different patterns I have i.e

string user = "\b(?:I|would|like|to|see|id|of|bought|good)\b";

but When I am matching string

string pattern = "^(?=.*\bgoods?|items?|things?\b)(?=.*\bbought\b)(?=.*\bid\b)(?=.*\btest\b).*$";

MatchCollection mat = Regex.Matches(pattern , user );

foreach (var item in mat)
{
    Console.WriteLine(item.ToString());
}

When matching the two above, the match collection only yields/collects match for (id, bought) but ignores "goods" from the first block of pattern. It seems to be ignoring **?** lookahead mentioned goods?|items?|things?.

Any suggestions.


Thanks

解决方案

"; MatchCollection mat = Regex.Matches(pattern , user ); foreach (var item in mat) { Console.WriteLine(item.ToString()); }

When matching the two above, the match collection only yields/collects match for (id, bought) but ignores "goods" from the first block of pattern. It seems to be ignoring **?** lookahead mentioned goods?|items?|things?.

Any suggestions.


Thanks

Hi,

Change your expression to this:

string pattern = "(?=.*\bgoods\b|\bitems\b|\bthings?\b)(?=.*\bbought\b)(?=.*\bid\b)(?=.*\btest\b).*";

Putting a ? after the 's' in 'things?' will catch both thing and things.

You need to have word boundaries around each word in the optional list.
(You also misspelled goods as good in your user input, but I assume you mean goods.)

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