Array.prototype.indexOf.call存在问题 [英] problems with Array.prototype.indexOf.call

问题描述

如果我单击一个元素Link1，则该函数中的e.target是节点Link1。我想知道这个节点在ul子节点中的索引是什么，在这种情况下我希望indexOf返回0因为Link1在0位置，而ii点击2我希望它是1.

If i click the a element "Link1" e.target in the function is the node Link1. I want to know in what index this node is in the ul children in this case i want indexOf to return 0 because Link1 is on position 0, and i i click 2 i want it to be 1.

HTML

<div class="link">
    <ul>
       <li><a>Link1</a></li>
       <li><a>Link2</a></li>
    </ul>
</div>

JAVASCRIPT

JAVASCRIPT

self.query('.link').forEach(function(linkNode, flikIndex, flikArr) { 
    dojo.query(linkNode, 'click', function(e) {
        var t = e.target; //If i click Link1 this is Link1 and if i click Link2 and so on. 
        var parent = t.parentNode; //Contains the parent to my a in this case li 
        var ancestor = t.parentNode.parentNode.childNodes; //Containes 2 li 
        var index = Array.prototype.indexOf.call(parent, ancestor); //Return -1 but i want it to return 0 because Link1 is on place [0] in the array.             

    }
}

请帮助我获得正确的索引

Please help me get the right index

推荐答案

var index = Array.prototype.indexOf.call(parent, ancestor);
//                                       ^ Array ^ Element in the array

所以你想要这个：

var index = Array.prototype.indexOf.call(ancestor, parent);

由于 ancestor 是元素（数组 ）包含 parent 。

Since ancestor is the element ("array") that contains parent.

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