查看传呼机的列表视图行项目 [英] View Pager as List View Row Item

问题描述

我有一个列表视图与20行，我想设置一个视图寻呼机作为一个列表视图中的每一行。作为项目进来我的列表视图可能的一个或一个以上，的行及欲使用视图寻呼机来显示列表视图行项目

I have a list view with 20 rows and I want to setup a view pager as each row in a list view. As the items coming in my row of the list view may one or more than one, and I want to show the list view row items using a view pager.

有关这一点，我现在用的是下面的code：

For this I am using the following code:

自定义布局将被显示在列表视图行（如寻呼机项目）

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:id="@+id/inner_layout"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:gravity="center"
    android:orientation="horizontal" >

    <ImageView
        android:id="@+id/icon"
        android:layout_width="wrap_content"
        android:layout_height="fill_parent"
        android:layout_marginRight="6.0dip"
        android:src="@drawable/ic_launcher" />

    <TextView
        android:id="@+id/text"
        android:layout_width="wrap_content"
        android:layout_height="fill_parent"
        android:gravity="center_vertical"
        android:text="Example Value"
        android:textAppearance="?android:textAppearanceMedium" />

有查看传呼机主列表视图自定义行项目

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="wrap_content"
    android:orientation="horizontal" >


         <android.support.v4.view.ViewPager
        android:id="@+id/mypager"
        android:layout_width="match_parent"
        android:layout_height="match_parent" />

</RelativeLayout>

MyPagerAdapter类

public class MyPagerAdapter extends PagerAdapter {

    private Context context;

    public MyPagerAdapter(Context context) {
        this.context = context;
    }

    @Override
    public int getCount() {
        return 4;
    }

    @Override
    public Object instantiateItem(View container, int position) {
        LayoutInflater inflater = (LayoutInflater) context
        .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        LinearLayout view = inflater.inflate(R.layout.inner_layout_file, null);
        ((ViewPager) container).addView(view, position);
        return view;
    }

    @Override
    public boolean isViewFromObject(View view, Object obj) {
        return view == ((View) obj);
    }

    @Override
    public void destroyItem(View container, int position, Object object) {
        // TODO Auto-generated method stub
        ((ViewPager) container).removeView((View) object);
    }
}

列表视图适配器，轻松实现视法

@Override
public View getView(int position, View convertView, ViewGroup parent) {


    LayoutInflater inflater = (LayoutInflater)context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    convertView = inflater.inflate(R.layout.horizontal_list_item, null,false);

    MyPagerAdapter adapter = new MyPagerAdapter(context);
    ViewPager myPager = (ViewPager) convertView.findViewById(R.id.mypager);
    myPager.setAdapter(adapter);

    myPager.setCurrentItem(0);

    return convertView;
}

我越来越没有错误，这是运行IT总是空后呈现的视图。任何人都可以请帮我什么，我做错了。

I AM GETTING NO ERROR AND THE VIEW WHICH IS RENDERED AFTER RUNNING IT ALWAYS EMPTY. cAN ANYONE PLEASE HELP ME WHAT I AM DOING WRONG.

谢谢

推荐答案

我也面临着同样的问题，由 getView（）方法。

I have faced the same issue and resolved it by providing id to the viewpager dynamically in the getView() method.

@Override
public View getView(int position, View convertView, ViewGroup parent) {


    LayoutInflater inflater = (LayoutInflater)context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    convertView = inflater.inflate(R.layout.horizontal_list_item, null,false);

    MyPagerAdapter adapter = new MyPagerAdapter(context);
    ViewPager myPager = (ViewPager) convertView.findViewById(R.id.mypager);

    **myPager.setId(position + getCount());**

    myPager.setAdapter(adapter);

    myPager.setCurrentItem(0);

    return convertView;
}

希望这可以帮助你。

Hope this may help you.

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