如何在python中使用urllib2进行基本HTTTP身份验证？ [英] How do I use urllib2 in python for Basic HTTTP Authentication?

问题描述

嘿伙计们，我正在尝试解决pentesterlabs认证部分中的一个问题，但我似乎无法做到正确。本质上，我试图在python中使用urllib2库进行基本的HTTP身份验证，但是尽管提供了正确的用户名和密码，我仍然会收到401：Unauthorized错误。我甚至打印出标题以确保它是正确的，我也对它进行了单独编码，它似乎也是正确的。有人可以告诉我我哪里错了吗？



<前lang =Python> ＃ 我编写的代码验证，HTTP，基本，身份验证，到目前为止
import urllib2
import base64
theurl = ' http://10.42.0.11/authentication/example2'
request = urllib2.Request（theurl）
try ：
handle = urllib2.urlopen（request）
IOError，e：
if hasattr（e，' code'）：
if e.code！= 401 ：
print ' 有些东西是se出了问题，你得到了一个不同的错误。'
print e.code
否则：
print e.headers
print e.headers [' www-authenticate']
＃ 登录的凭据是黑客：pentesterlab
＃ 下面你可以看到凭证的base64编码版本
request.add_header（ 授权， 基本％s％ aGFja2VyOnBlbnRlc3RlcmxhYgo =）
print request.headers
handle = urllib2.urlo笔（请求）

解决方案

Hey guys, I am trying to solve one of the problems in the authentication section of pentesterlabs but I just can't seem to get it right. In essence, I am trying to use the urllib2 library in python for basic HTTP authentication, however despite providing the correct username and password I keep getting a 401: Unauthorized error. I even print out the header to make sure that it is correct, and I also base64 encoded it separately and it also seems to be correct. Can anybody please show me where I am going wrong?

#The code I have written Authentication, HTTP, Basic, Authentication, so far
import urllib2
import base64
theurl = 'http://10.42.0.11/authentication/example2'
request = urllib2.Request(theurl)
try:
  handle = urllib2.urlopen(request)
except IOError, e:
  if hasattr(e, 'code'):
    if e.code != 401:
      print 'Something is seriously wrong, you got a different error.'
      print e.code
    else:
      print e.headers
      print e.headers['www-authenticate']
#The credentials for login in are hacker:pentesterlab
#Below you can see the base64 encoded version of the credentials
request.add_header("Authorization", "Basic %s"%"aGFja2VyOnBlbnRlc3RlcmxhYgo=") 
print request.headers
handle = urllib2.urlopen(request)

解决方案

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