我会在这里使用什么数学函数？ [英] What Math Function Would I Use Here?

问题描述

我是一名初学程序员，并且被要求创建一个程序，要求用户给出三角形斜边的长度，程序假设三角形是一个30,60,90度的三角形（右边）三角）并给另外两边。



我得到了那边a = hyp * Cos（30）和b = hyp * Sin（30）。我只是不确定如何在C中使用数学库函数。这是我的代码到目前为止：

 {
  float 斜边; 
 
 printf（ 输入斜边的长度：）; 
 scanf（ ％f，& hypotenuse）; 
 printf（ 您输入的是斜边=％9.2f \ n，斜边）; 
} 

解决方案

请查看我对该问题的评论，并尝试至少更加独立。到目前为止，你并没有处于最小的工作状态。 :-)



使用C，你可以使用math.h：

http://www.techonthenet.com/c_language/standard_library_functions/math_h/cos.php [ ^ ]，

http://www.techonthenet.com/c_language/standard_library_functions/math_h/sin.php [ ^ ]。



使用C ++和tmath.h，您可以使用函数的类型通用宏版本：

http://www.cplusplus.com/reference/cmath/cos [ ^ ]，

http：//www.cplusplus。 com / reference / cmath / sin / [ ^ ]。

-SA

你可能想要开始这里 [ ^ ]



通过Googling C＃trig函数得到它。

实际上你甚至不需要三角函数。你的直角三角形恰好是等长三角形的一半。所以 a 非常简单，只需要 sqrt 来查找 b

I am a beginning programmer and have been asked to create a program that asks the user to give length for a hypotenuse of a Triangle and the program is supposes to assume that the Triangle is a 30,60,90 degree triangle (right triangle) and give the other two sides.

I was given that side a=hyp*Cos(30) and b=hyp*Sin(30). Im just not sure how to use the math library functions in C. Here is my code so far:

{
float hypotenuse;

printf("Enter the length of the hypotenuse:");
scanf("%f", &hypotenuse);
printf("You have entered that the hypotenuse=%9.2f\n",hypotenuse);
}

解决方案

Please see my comments to the question and try to become at least a bit more independent. So far, you are not in a minimal working shape. :-)

With C, you can use "math.h":
http://www.techonthenet.com/c_language/standard_library_functions/math_h/cos.php[^],
http://www.techonthenet.com/c_language/standard_library_functions/math_h/sin.php[^].

With C++ and "tmath.h", you could have type-generic macro version of the functions:
http://www.cplusplus.com/reference/cmath/cos[^],
http://www.cplusplus.com/reference/cmath/sin/[^].

—SA

You'd probably want to start here [^]

Got that by Googling C# trig functions.

Actually you didn't even need trigonometric functions. Your right triangle is exactly the half on an equilater one. So a is really simple to know while you just need sqrt to findo out b.

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