HttpWebRequest.GetResponse（）在尝试发布文件时总是在计时 [英] HttpWebRequest.GetResponse() Always Timing Out When Trying to Post File
问题描述
嗨！
尝试将文件发布到php脚本时遇到问题。
我知道100％确保URL正确并且可以访问php脚本。我100％知道我要上传的文件存在。
当我尝试上传时，.GetResponse（）方法超时。有时它抛出异常：底层连接已关闭：接收时发生意外错误
这是我的文件上传代码：
public static string PostData（ string strUrl， string strFileToUpload）
{
< span class =code-keyword> try
{
const string strFileFormName = file;
var oUri = new Uri（strUrl）;
var strBoundary = ---- ------ + DateTime.Now.Ticks.ToString（ x）;
// 尾随边界字符串
var boundaryBytes = Encoding.ASCII.GetBytes（ \\\\ n - + strBoundary + \\\\ n）;
// 帖子邮件标题
var sb = new StringBuilder（）;
sb.Append（ - ）;
sb.Append（strBoundary）;
sb.Append（ \\\\ n）;
sb.Append（ Content-Disposition：form-data; name = \）;
sb.Append（strFileFormName）;
sb.Append（ \ ; filename = \）;
sb.Append（Path.GetFileName（strFileToUpload））;
sb.Append（ \）;
sb.Append（ \\\\ n）;
sb.Append（ Content-Type：）;
sb.Append（ application / octet-stream）;
sb.Append（ \\\\ n）;
sb.Append（ \\\\ n）;
var strPostHeader = sb.ToString（）;
var postHeaderBytes = Encoding.UTF8.GetBytes（strPostHeader）;
// WebRequest
var oWebrequest =（HttpWebRequest）WebRequest.Create（oUri）;
oWebrequest.ContentType = multipart / form-data; boundary = + strBoundary;
oWebrequest.Method = POST;
oWebrequest.Timeout = Timeout.Infinite;
oWebrequest.KeepAlive = true ;
// 这很重要，否则无论如何整个文件都将被读入内存......
oWebrequest.AllowWriteStreamBuffering = true ;
// 获取FileStream并设置WebRequest的最终属性
var oFileStream = new FileStream（strFileToUpload，FileMode.Open，FileAccess.Read）;
var length = postHeaderBytes.Length + oFileStream.Length + boundaryBytes.Length;
oWebrequest.ContentLength = length;
var oRequestStream = oWebrequest.GetRequestStream（）;
// 写邮件标题
oRequestStream.Write（ postHeaderBytes， 0 ，postHeaderBytes.Length）;
// 将文件内容分成小块（最多4096字节）。
// byte [] buffer = new Byte [checked（（uint）Math.Min（4096） ，（int）oFileStream.Length））];
var buffer = new 字节 [已检查（（ uint ） oFileStream.Length）];
var bytesRead = 0 ;
while （（bytesRead = oFileStream.Read（buffer， 0 ，buffer.Length）） ！= 0 ）
oRequestStream.Write（buffer， 0 ，bytesRead）;
oFileStream.Close（）;
// 添加尾随边界
oRequestStream.Write（ boundaryBytes， 0 ，boundaryBytes.Length）;
var oWResponse = oWebrequest.GetResponse（）;
var s = oWResponse.GetResponseStream（）;
if （s！= null ）
{
var sr = new StreamReader（s）;
var sReturnString = sr.ReadToEnd（）;
// 清理
oFileStream.Close（）;
oRequestStream.Close（）;
s.Close（）;
sr.Close（）;
return sReturnString;
}
}
catch { return 字符串 .Empty; }
return String .Empty;
}
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这是我在服务器端的PHP代码：
< pre lang =PHP> <？php
require（' vars.php'）;
$ dbHost = DB_HOST; // MySQL主机
$ dbUser = DB_USER; // MySQL用户名
$ dbPass = DB_PASSWORD; // MySQL密码
$ dbDatabase = DB_NAME; // MySQL数据库名称
function connect_database（）{
global $ dbHost，$ dbUser，$ dbPass， $ dbDatabase ;
$ mysql = mysql_connect（DB_HOST，DB_USER，DB_PASSWORD）;
if （！$ mysql）{
$ html 。= 数据库错误。$ header。 无法连接数据库，请检查配置。。$ footer;
die（$ html）;
}
if （！mysql_select_db（$ dbDatabase，$ mysql））{
mysql_close（$ mysql）;
$ html 。= 数据库错误 。$ header。 无法选择'。$ dbDatabase。 '数据库，请检查配置。。$ footer;
die（$ html）;
}
return $ mysql ;
}
connect_database（）;
$ ID = getRandomString（）;
$ Location = stats /.$ID. 。html;
if（is_uploaded_file（$ _ FILES [' file'] [' tmp_name']））
{
if （move_uploaded_file（$ _ FILES [' file'] [' tmp_name'] [0]，$ Location））{
mysql_query（ INSERT INTO`user_stat_links`（`s_id`）VALUES（'。$ ID。 '））
或 die（mysql_error（））;
echo http：// myurl。 COM /统计/ ID = $ ID？。
退出;
}
}
echo 错误;
？>
我非常困惑这个。我之前使用过这个c＃代码来上传文件，它已经100％正常工作了。
请帮忙！ dbHost
= DB_HOST; // MySQL主机
dbUser
= DB_USER; // MySQL用户名
dbPass
= DB_PASSWORD; // MySQL密码
I'm having an issue when trying to post a file to a php script.
I know 100% sure that the URL is correct and the php script is accessible. I know 100% that the file I'm trying to upload exists.
When I try and upload, the .GetResponse() method times out. Sometimes it throws the exception: "The underlying connection was closed: An unexpected error occurred on a receive"
Here's my file upload code:
public static string PostData(string strUrl, string strFileToUpload)
{
try
{
const string strFileFormName = "file";
var oUri = new Uri(strUrl);
var strBoundary = "----------" + DateTime.Now.Ticks.ToString("x");
// The trailing boundary string
var boundaryBytes = Encoding.ASCII.GetBytes("\r\n--" + strBoundary + "\r\n");
// The post message header
var sb = new StringBuilder();
sb.Append("--");
sb.Append(strBoundary);
sb.Append("\r\n");
sb.Append("Content-Disposition: form-data; name=\"");
sb.Append(strFileFormName);
sb.Append("\"; filename=\"");
sb.Append(Path.GetFileName(strFileToUpload));
sb.Append("\"");
sb.Append("\r\n");
sb.Append("Content-Type: ");
sb.Append("application/octet-stream");
sb.Append("\r\n");
sb.Append("\r\n");
var strPostHeader = sb.ToString();
var postHeaderBytes = Encoding.UTF8.GetBytes(strPostHeader);
// The WebRequest
var oWebrequest = (HttpWebRequest)WebRequest.Create(oUri);
oWebrequest.ContentType = "multipart/form-data; boundary=" + strBoundary;
oWebrequest.Method = "POST";
oWebrequest.Timeout = Timeout.Infinite;
oWebrequest.KeepAlive = true;
// This is important, otherwise the whole file will be read to memory anyway...
oWebrequest.AllowWriteStreamBuffering = true;
// Get a FileStream and set the final properties of the WebRequest
var oFileStream = new FileStream(strFileToUpload, FileMode.Open, FileAccess.Read);
var length = postHeaderBytes.Length + oFileStream.Length + boundaryBytes.Length;
oWebrequest.ContentLength = length;
var oRequestStream = oWebrequest.GetRequestStream();
// Write the post header
oRequestStream.Write(postHeaderBytes, 0, postHeaderBytes.Length);
// Stream the file contents in small pieces (4096 bytes, max).
//byte[] buffer = new Byte[checked((uint)Math.Min(4096, (int)oFileStream.Length))];
var buffer = new Byte[checked((uint)oFileStream.Length)];
var bytesRead = 0;
while ((bytesRead = oFileStream.Read(buffer, 0, buffer.Length)) != 0)
oRequestStream.Write(buffer, 0, bytesRead);
oFileStream.Close();
// Add the trailing boundary
oRequestStream.Write(boundaryBytes, 0, boundaryBytes.Length);
var oWResponse = oWebrequest.GetResponse();
var s = oWResponse.GetResponseStream();
if (s != null)
{
var sr = new StreamReader(s);
var sReturnString = sr.ReadToEnd();
// Clean up
oFileStream.Close();
oRequestStream.Close();
s.Close();
sr.Close();
return sReturnString;
}
}
catch { return String.Empty; }
return String.Empty;
}
here's my PHP code on the server end:
<?php
require('vars.php');
$dbHost = DB_HOST; // MySQL host
$dbUser = DB_USER; // MySQL username
$dbPass = DB_PASSWORD; // MySQL password
$dbDatabase = DB_NAME; // MySQL database name
function connect_database() {
global $dbHost, $dbUser, $dbPass, $dbDatabase;
$mysql = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if (!$mysql) {
$html .= "Database Error".$header."Can not connect to database, please check the configuration.".$footer;
die($html);
}
if (!mysql_select_db($dbDatabase, $mysql)) {
mysql_close($mysql);
$html .= "Database Error".$header."Can not select '".$dbDatabase."' database, please check the configuration.".$footer;
die($html);
}
return $mysql;
}
connect_database();
$ID = getRandomString();
$Location = "stats/".$ID.".html";
if(is_uploaded_file($_FILES['file']['tmp_name']))
{
if (move_uploaded_file($_FILES['file']['tmp_name'][0], $Location)) {
mysql_query("INSERT INTO `user_stat_links` (`s_id`)VALUES('".$ID."')")
or die(mysql_error());
echo "http://myurl.com/stats/?id=".$ID;
exit;
}
}
echo "error";
?>
I'm extremely baffled by this. I've used this c# code before to upload files and it has worked 100% fine.
Please help!dbHost
= DB_HOST; // MySQL host
dbUser
= DB_USER; // MySQL username
dbPass
= DB_PASSWORD; // MySQL password
