N在Asp Web中使用下拉控件从此代码工作正常但是当我在Asp Winform中使用此代码时它给我错误我能做什么？ [英] N Using Dropdown Control In Asp Web From With This Code Its Work Fine But When I Use This Code In Asp Winform Its Give Me Error What I Can Do?

问题描述

private void populatesocietyname（）

{

string CS = ConfigurationManager.ConnectionStrings [SocietyCS] .ConnectionString;

使用（SqlConnection con = new SqlConnection（CS））

{

SqlCommand cmd = new SqlCommand（select SocietyID，SocietyFullName from tblsociety，con）;

con.Open（）;

SqlDataReader rdr = cmd.ExecuteReader（）;

ddlsocietyname.DataTextField =SocietyFullName;

ddlsocietyname.DataValueField =SocietyID;

ddlsocietyname.DataSource = grdr;

ddlsocietyname.DataBind（）;

ddlsocietyname .Items.Insert（0，n

ew ListItem（ - 选择社会名称 - ，0））;

}

}



这个win形式的代码给出错误我试图cha nge datatext to valued显示一个datavaluefield到valuisplay但它在datasource给出错误我怎么解决这个？

解决方案

尝试下面

 ddlsocietyname。 DisplayMember  =   SocietyFullName; 
 ddlsocietyname。 ValueMember  =   SocietyID; 
 ddlsocietyname.DataSource = grdr; 
   //   ddlsocietyname.DataBind（）;   

private void populatesocietyname()
{
string CS = ConfigurationManager.ConnectionStrings["SocietyCS"].ConnectionString;
using (SqlConnection con = new SqlConnection(CS))
{
SqlCommand cmd = new SqlCommand("Select SocietyID,SocietyFullName from tblsociety", con);
con.Open();
SqlDataReader rdr = cmd.ExecuteReader();
ddlsocietyname.DataTextField = "SocietyFullName";
ddlsocietyname.DataValueField = "SocietyID";
ddlsocietyname.DataSource = grdr;
ddlsocietyname.DataBind();
ddlsocietyname.Items.Insert(0, n
ew ListItem("-- Select Society Name --", "0"));
}
}

This code in win form give error i tried to change the datatext to valuedisplay a datavaluefield to valuedisplay but it give error at datasource how i can solve this?

解决方案

try below

ddlsocietyname.DisplayMember = "SocietyFullName";
ddlsocietyname.ValueMember = "SocietyID";
ddlsocietyname.DataSource = grdr;
//ddlsocietyname.DataBind();

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