需要帮助才能获得正则表达式 [英] need help to get regex pattern

问题描述

我想从以下html代码中提取一些值。

Hi, I want to extract some value from the following html code.

<a class="listing-name" title="view more about this business" 

                href="/nsw/sydney/paul-paul-laywers-12345678-
               listing.html?referredby =www.yellowpages.com.au& 
                context=businesstypesearch"></a>

我想得到一个价值paul-paul来自上面的HTML代码的律师。

我尝试使用Expresso自己。但我无法达到结果。

拜托，建议我正确的正则表达式模式。



谢谢。

I want to get a value paul-paul-lawyers from the above html code.
I tried my self using Expresso. but I could not achieve the result.
please, suggest me correct regex pattern for this.

Thanks.

推荐答案

试试：

Try:

(?<=href=")(?:\w*/)*(.*)(?:-[^-]*)(?:-[^-]*)(?=\.html)

试试这个：

Try this:

(?<=/)[a-zA-Z\-]+(?=\-\d)

这将匹配任何' - '分隔的字母以'/'开头并以'结尾' - '和数字但不包括在内。

This will match any '-' delimited alphabets starts with '/' and end with a '-' and number but both not inclusive.

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