我如何将图形放入此程序并使用Visual Studio 2012 [英] How Can I Put Graphics In This Program And Im Using Visual Studio 2012
本文介绍了我如何将图形放入此程序并使用Visual Studio 2012的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
#include < iostream.h >
#include < stdlib.h >
#include < string.h >
#include < conio.h >
const int MAXLENGTH = 20 ;
const int MAX_TRIES = 5 ;
const int MAXROW = 7 ;
int letterFill（ char ， char []， char []）;
void initUnknown（ char []， char []）;
int main（）
{
clrscr（）;
char unknown [MAXLENGTH];
char letter;
int num_of_wrong_guesses = 0 ;
char 字[MAXLENGTH];
char words [] [MAXLENGTH] =
{
dadu，
haala，
jamshoro，
karachi，
mithi，
nawabshah，
rohri，
sukkur，
thatta ，
umerkot
};
// 随机选择并复制单词数组
randomize（）;
int n = random（ 10 ）;
strcpy（word，words [n]）;
// 使用*字符初始化密码。
initUnknown（word，unknown）;
// 欢迎用户
cout<< \ n \ n欢迎来到游戏......猜猜海德拉巴城市名称;
cout<< \ n \ n每个字母由星号表示 - >'*';
cout<< \ n \ n您只需在一次尝试中键入一个字母;
cout<< \ n \ n你有<< MAX_TRIES<< 尝试猜测正确的城市名称。;
cout<< \ n ~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~~~~~~~~~~;
// 循环直到猜测用完
< span class =code-keyword> while （num_of_wrong_guesses< MAX_TRIES）
{
cout<< \ n \ n<<未知;
cout<< \ n \ n取一封信：;
cin>>信件;
// 如果猜测正确，请用字母填写密码，
< span class =code-comment> // 否则增加错误猜测的数量。
if （letterFill（字母，单词，未知）== 0 ）
{
cout<< endl<< 哎呀！那封信不在那里！<< ENDL;
num_of_wrong_guesses ++;
}
else
{
cout<< endl<< 你找到了一封信！不是那么令人兴奋的Dude（Y）< *！*><< ENDL;
}
// 告诉用户剩下多少猜测。
cout<< 您有<< MAX_TRIES - num_of_wrong_guesses;
cout<< 猜对了。<< ENDL;
// 检查他们是否猜到了这个词。
if （strcmp（word，unknown）== 0 ）
{
cout<<单词<< ENDL;
cout<< 是的！你明白了！;
break ;
}
}
如果（num_of_wrong_guesses == MAX_TRIES）
{
cout< ;< \ n抱歉，你输了......你被绞死了。<< ENDL;
cout<< 这个词是：<<单词<< ENDL;
}
getch（）;
return 0 ;
}
/ * 取一个字符猜测和密码，填写
未完成的猜测。返回匹配的字符数。
此外，如果已经猜到了字符，则返回零。 * /
int letterFill（ char guess， char secretword []， char guessword []）
{
int i;
int matches = 0 ;
for （i = 0 ; secretword [i]！= ' \ 0'; i ++）
{
// 我们之前的猜测中是否已匹配此字母？
if （guess == guessword [i]）
return 0 ;
// 这个秘密字是猜测吗？
if （guess == secretword [i]）
{
guessword [i] = guess;
匹配++;
}
}
返回匹配;
}
// 初始化未知单词
void initUnknown（ char word []， char unknown []）
{
int i;
int length = strlen（word）;
for （i = 0 ; i< length; i ++）
unknown [i] = ' *';
unknown [i] = ' \0';
}
解决方案
基本上，你没有。
这是一个控制台应用，控制台只支持文本。
如果你想使用图形，那么你需要查看一个Windows应用程序 - 也许是一个WinForms应用程序？
通常你在Windows GUI应用程序中使用图形。这种应用程序的开发与您所做的非常不同（Console one）。您可以开始阅读像
theForger的Win32 API编程教程这样的教程。 a href =http://www.winprog.org/tutorial/start.htmltarget =_ blanktitle =New Window> ^ ]（这是一种'对金属'的发展，您也可以查看一个框架，例如MFC）。
您可以输出艺术品：
（例子）http://chris.com/ascii/
（ascii art generator example） http://www.glassgiant.com/ascii/ [ ^
#include <iostream.h>
#include <stdlib.h>
#include <string.h>
#include <conio.h>
const int MAXLENGTH=20;
const int MAX_TRIES=5;
const int MAXROW=7;
int letterFill (char, char[], char[]);
void initUnknown (char[], char[]);
int main ()
{
clrscr();
char unknown [MAXLENGTH];
char letter;
int num_of_wrong_guesses=0;
char word[MAXLENGTH];
char words[][MAXLENGTH] =
{
"dadu",
"haala",
"jamshoro",
"karachi",
"mithi",
"nawabshah",
"rohri",
"sukkur",
"thatta",
"umerkot"
};
//choose and copy a word from array of words randomly
randomize();
int n=random(10);
strcpy(word,words[n]);
// Initialize the secret word with the * character.
initUnknown(word, unknown);
// welcome the user
cout << "\n\nWelcome To The Game...Guess a Hyderabad Cities Name";
cout << "\n\nEach letter is represented by a star -> '*'";
cout << "\n\nYou have to type only one Alphabet in one try";
cout << "\n\nYou have " << MAX_TRIES << " tries to try and guess the correct City name.";
cout << "\n~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~";
// Loop until the guesses are used up
while (num_of_wrong_guesses < MAX_TRIES)
{
cout << "\n\n" << unknown;
cout << "\n\nGuess a letter: ";
cin >> letter;
// Fill secret word with letter if the guess is correct,
// otherwise increment the number of wrong guesses.
if (letterFill(letter, word, unknown)==0)
{
cout << endl << "Whoops! That letter isn't in there!" << endl;
num_of_wrong_guesses++;
}
else
{
cout << endl << "You found a letter! Isn't that exciting Dude (Y) <*!*>" << endl;
}
// Tell user how many guesses has left.
cout << "You have " << MAX_TRIES - num_of_wrong_guesses;
cout << " guesses left." << endl;
// Check if they guessed the word.
if (strcmp(word, unknown) == 0)
{
cout << word << endl;
cout << "Yeah! You got it!";
break;
}
}
if(num_of_wrong_guesses == MAX_TRIES)
{
cout << "\nSorry, you lose...you've been hanged." << endl;
cout << "The word was : " << word << endl;
}
getch();
return 0;
}
/* Take a one character guess and the secret word, and fill in the
unfinished guessword. Returns number of characters matched.
Also, returns zero if the character is already guessed. */
int letterFill (char guess, char secretword[], char guessword[])
{
int i;
int matches=0;
for (i = 0; secretword[i]!='\0'; i++)
{
// Did we already match this letter in a previous guess?
if (guess == guessword[i])
return 0;
// Is the guess in the secret word?
if (guess == secretword[i])
{
guessword[i] = guess;
matches++;
}
}
return matches;
}
// Initialize the unknown word
void initUnknown (char word[], char unknown[])
{
int i;
int length = strlen(word);
for (i = 0; i < length; i++)
unknown[i]='*';
unknown[i]='\0';
} 解决方案
Basically, you don't.
That is a console app, and the Console only supports text.
If you want to use graphics, then you need to look at a Windows application - perhaps a WinForms app?
Typically you use graphics in a Windows GUI application. The development of such kind of application is very different from the one you did (a Console one). You could start reading a tutorial like
"theForger's Win32 API Programming Tutorial"[^] (this is a kind of 'to the metal' development, you may also check out a framework, like for instance,MFC).
you can output acii art:
(examples) http://chris.com/ascii/
(ascii art generator example) http://www.glassgiant.com/ascii/[^]
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