如何在noticeID上使用group by子句来选择linq中的所有这些字段 [英] how to use group by clause on the noticeID to select all these field in linq
本文介绍了如何在noticeID上使用group by子句来选择linq中的所有这些字段的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
var notice =( from n 在 context.Notice
join nd 在上下文中。 NoticeDetail
on n.ID等于nd.NoticeID
其中 nd.SenderLocationID == locationID&& nd.SenderActionID == sent& & nd.Title!=
选择 new
{
NoticeID = nd.NoticeID,
NoticeDetailID = nd.ID,
From =(currentLanguage == enmLanguage.English)?nd.SenderPanchaya tiRajLocation.Name:nd.SenderPanchayatiRajLocation.NameRegional,
Subject = nd.Title,
Date = nd.CreatedOn,
Priority =(currentLanguage == enmLanguage.English)? n.Priority.Name:n.Priority.Name_Regional,
SentMail = context.NoticeRecipients.Where(a = > a.NoticeDetailID == nd.ID ).Count(),
回复= context.NoticeRecipients.Where(a = > a.ReceiverLocationID == locationID&&(a.ReceiverActionID ==收到|| a.ReceiverActionID == read)&& a.NoticeDetail.NoticeID == nd.NoticeID).Count()
})。Distinct();
notice = notice.OrderBy(s = > s.Priority).ThenBy(s = > s.Date);
PagingBar1.Bind(注意, ref gvReceive);
解决方案
< blockquote>对不起,但不清楚你在问什么?
var gitms = notice.GroupBy(g => g.NoticeID);
var notice = (from n in context.Notice
join nd in context.NoticeDetail
on n.ID equals nd.NoticeID
where nd.SenderLocationID == locationID && nd.SenderActionID == sent && nd.Title !=""
select new
{
NoticeID = nd.NoticeID,
NoticeDetailID = nd.ID,
From = (currentLanguage == enmLanguage.English) ? nd.SenderPanchayatiRajLocation.Name : nd.SenderPanchayatiRajLocation.NameRegional,
Subject = nd.Title,
Date = nd.CreatedOn,
Priority = (currentLanguage == enmLanguage.English) ? n.Priority.Name : n.Priority.Name_Regional,
SentMail = context.NoticeRecipients.Where(a => a.NoticeDetailID == nd.ID).Count(),
Replies = context.NoticeRecipients.Where(a => a.ReceiverLocationID == locationID && (a.ReceiverActionID == received || a.ReceiverActionID == read) && a.NoticeDetail.NoticeID == nd.NoticeID).Count()
}).Distinct();
notice = notice.OrderBy(s => s.Priority).ThenBy(s => s.Date);
PagingBar1.Bind(notice, ref gvReceive);
解决方案
Sorry, but not clear what you are asking?
var gitms = notice.GroupBy(g => g.NoticeID);
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