如何将csv文件读入结构数组 [英] How to read csv file into structure array

问题描述

如何将.csv文件读入结构数组？我能够将.txt文件读入结构数组。



尝试使用getline但它不起作用。

  void  loadsn（SN_curve sncurve [ 6 ]）
 {
 ifstream infile; 
  int  totalData =  0 ; 
 string  value ; 
 infile.open（  Curve.txt）; 
 
  if （infile.is_open（））
 {
 
 执行 {
 
 infile>> sncurve [totalData] .material>> sncurve [totalData] .SFP>> sncurve [totalData] .slope>> sncurve [totalData] .elast_mod>> sncurve [totalData] .poisson>> sncurve [totalData] .km; 
 
 totalData ++; 
 
}  while （！infile.eof（））; 
 
 infile.close（）; 
} 
 
} 

curve.csv文件。



焊接连接R1,48.5,4,1000,0.3,0.0，

焊接连接R2,234,5,2000,0.3,0.0

解决方案

您最好读取文件的每一行，并将整行解析为正确的值。



写一行解析函数。



我会为每一行创建一个类。

How to read .csv file into structure array? I am able to read .txt file into structure array.

tried with getline but it doesn't work.

void loadsn(SN_curve sncurve[6])
 {
	ifstream infile;
	int totalData = 0;
	string value;
             infile.open("Curve.txt");

   if (infile.is_open())
   {

      do {

        infile >>sncurve[totalData].material>>sncurve[totalData].SFP >> sncurve	            [totalData].slope>>sncurve[totalData].elast_mod >>sncurve[totalData].poisson >>sncurve	            [totalData].km;
		  
             totalData++;

          } while (!infile.eof());

             infile.close();
   }

}

curve.csv file.

Weld join R1 , 48.5,4 ,1000, 0.3 ,0.0,
Weld join R2 , 234, 5, 2000, 0.3,0.0

解决方案

you better read each line of the file and parse the complete line to the right values.

Write a line parsing function.

I would create a class for each line.

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