Android的删除按钮动态 [英] Android remove button dynamically

问题描述

我有一个按钮，当我preSS它，我想删除它（不能使它不可见）。我看，我能做到这一点使用 layout.removeView（myButton的），但什么是布局？我怎样才能得到它在我的活动

 按钮showQuestion;
私人无效初始化（）{
    showQuestion =（按钮）findViewById（R.id.bAnswerQuestionShowQuestion）;
}
公共无效的onClick（视图v）{
    开关（v.getId（））{
        案例R.id.bAnswerQuestionShowQuestion：
                showQuestion.setVisibility（View.INVISIBLE）;
                //这里我要删除的按钮
                question.setVisibility（View.VISIBLE）;
                theAnswer.setVisibility（View.VISIBLE）;
                answerQuestion.setVisibility（View.VISIBLE）;
                showChoices.setVisibility（View.VISIBLE）;
                showHint.setVisibility（View.VISIBLE）;
            打破;
    }
}
 

解决方案

看链接

 的ViewGroup布局=（ViewGroup中）button.getParent（）;
如果（NULL！=布局）//为了安全只能作为你正在做的onClick
  layout.removeView（按钮）;
 

I have a button and when I press it, i want to remove it (not make it invisible). I read that I can do that using layout.removeView(mybutton) but what is the layout ? and how can I get it in my activity

Button showQuestion;
private void initialize() {
    showQuestion = (Button) findViewById(R.id.bAnswerQuestionShowQuestion);
}
public void onClick(View v) {
    switch (v.getId()) {
        case R.id.bAnswerQuestionShowQuestion:
                showQuestion.setVisibility(View.INVISIBLE);
                //Here i want to delete the button
                question.setVisibility(View.VISIBLE);
                theAnswer.setVisibility(View.VISIBLE);
                answerQuestion.setVisibility(View.VISIBLE);
                showChoices.setVisibility(View.VISIBLE);
                showHint.setVisibility(View.VISIBLE);
            break;
    }
}

解决方案

see link

ViewGroup layout = (ViewGroup) button.getParent();
if(null!=layout) //for safety only  as you are doing onClick
  layout.removeView(button);

这篇关于Android的删除按钮动态的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！