如何从网格视图中获取下拉值我正在动态添加下拉列表 [英] How To Get Dropwdown Value From The Grid View I Am Adding Dropdown Dynamically

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问题描述

美好的一天,







我有一个网格我正在动态创建模板字段代码背后,我正在动态添加下拉列表它正在成功添加



当我尝试从循环中获取网格的dropwdown值时,gridview正在显示问题它给了我错误



无法将'System.Web.UI.WebControls.GridViewRow'类型的对象强制转换为'System.Web.UI.WebControls.GridView'。



i我循环播放按钮上的网格视图点击她的代码



我的班级文件



Good Day,

Hi

I have a grid i am creating template fields dynamically from code behind and i am adding dropdown dynamically it is being added sucessfully

the gridview is being show problemis when i try to get the dropwdown value from grid from looping it gives me error

Unable to cast object of type 'System.Web.UI.WebControls.GridViewRow' to type 'System.Web.UI.WebControls.GridView'.

i am looping throgh the grid view on a button click hers my code

My class file

/// <summary>
/// Summary description for MyGridViewTemplate
/// </summary>
public class MyGridViewTemplate : ITemplate
{
private DataControlRowType templateType;
private string columnName;

public MyGridViewTemplate(DataControlRowType type, string colname)
{
templateType = type;
columnName = colname;
}

public void InstantiateIn(System.Web.UI.Control container)
{
// Create the content for the different row types.
switch (templateType)
{
case DataControlRowType.Header:
// Create the controls to put in the header section and set their properties.
Literal lc = new Literal();
lc.Text = "" + columnName + "";
// Add the controls to the Controls collection of the container.
container.Controls.Add(lc);
break;
case DataControlRowType.DataRow:
// Create the controls to put in a data row section and set their properties.
DropDownList firstName = new DropDownList();
firstName.ID = "ddl";
Label lastName = new Label();
for (int i = 0; i < 2; i++)
{
firstName.Items.Add(new ListItem(i.ToString(), i.ToString()));

}
// Add the controls to the Controls collection of the container.
container.Controls.Add(firstName);

break;

// Insert cases to create the content for the other row types, if desired.

default:
// Insert code to handle unexpected values.
break;
}
}





和她的my.cs文件



and her's my.cs file

protected void Page_Load(object sender, EventArgs e)
{

////Populate Data
DataTable dt = new DataTable();
dt.Columns.Add("Links");
dt.Columns.Add("Links1");
DataRow dr;
for (int i = 1; i < 10; i++)
{
dr = dt.NewRow();
dr["Links"] = "A" + i;
dr["Links1"] = "B" + i;
dt.Rows.Add(dr);
dt.AcceptChanges();
}
////Grid view
// The field columns need to be created only when the page is first loaded. 
if (!IsPostBack)
{
gvTest.AutoGenerateColumns = false;
// Dynamically create field columns to display the desired
// fields from the data source. Create a TemplateField object 
// to display an author's first and last name.
TemplateField customField = new TemplateField();
// Create the dynamic templates and assign them to 
// the appropriate template property.
for (int i = 0; i < 10; i++)
{
customField = new TemplateField();
customField.HeaderTemplate = new MyGridViewTemplate(DataControlRowType.Header,i.ToString());
customField.ItemTemplate = new MyGridViewTemplate(DataControlRowType.DataRow,i.ToString());
// Add the field column to the Columns collection of the GridView control.
this.gvTest.Columns.Add(customField);
}

// Add the field column to the Columns collection of the GridView control.
this.gvTest.Columns.Add(customField);
BoundField boundField = new BoundField();
boundField.HeaderText = "Bug ID";
boundField.DataField = "Links";
this.gvTest.Columns.Add(boundField);

gvTest.DataSource = dt;
gvTest.DataBind();

}
}
protected void ButtonShow(object sender, EventArgs e)
{


foreach (GridViewRow grow in gvTest.Rows)
{
DropDownList ddl = (DropDownList)grow.FindControl("ddl");
}
}









我我在这一行得到错误

DropDownList ddl =(DropDownList)grow.FindControl(ddl);





I am getting Error on this line
DropDownList ddl = (DropDownList)grow.FindControl("ddl");

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