从PHP COM返回值 [英] Return Value from PHP COM
本文介绍了从PHP COM返回值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在为.NET应用程序编写一个控制面板。使用COM类我能够成功运行方法,但我无法查看返回值。我期待-1到13之间的值。
<?php
$ archivals = new COM(' Unreal.ArchivalCtrl',NULL,CP_UTF8)或 die( ' 无法启动Archival Com');
// 打开COM
$ archivals-> ManualStart(' localhost',' < span class =code-string> test',true,false);
// 让我们开始在服务器上录制视频
$ status = new Variant(NULL);
// 将变量var设置为空
$ status = $ archivals-> GetSourceStatus(' localhost',' test');
// 让我们确保记录,获取状态
$ s = print_r($ status);
// 将状态转换为字符串
echo $ s;
// 查看状态
?>
输出为:'variant Object 1'
我尝试过variant_get_type以及var_dump但没有成功。
这是链接到我正在使用的API。
提前感谢您的帮助
解决方案
archivals = new COM(' Unreal.ArchivalCtrl',NULL,CP_UTF8)或 die(' 无法启动Archival Com');
// 打开COM
archivals- > ManualStart(' localhost',' test',true,false);
// 让我们开始在服务器上录制视频
status = new Variant(NULL);
// 将变量var设置为空
I am writing a control panel for a .NET application. Using the COM class I am able to run methods successfully, but I am unable to view a return value. I am expecting a value between -1 though 13.
<?php
$archivals = new COM('Unreal.ArchivalCtrl', NULL, CP_UTF8) or die ('Unable to Launch Archival Com');
//Open up COM
$archivals->ManualStart('localhost', 'test', true, false);
//Lets start recording a video on the server
$status = new Variant(NULL);
//Set variant var to nothing
$status = $archivals->GetSourceStatus('localhost', 'test');
//Lets make sure it's recording, get a status
$s = print_r($status);
//Convert status to string
echo "$s";
//View status
?>
The output is: 'variant Object 1'
I have tried variant_get_type as well as var_dump with no success.
Here is the link to the API I am working with.
Thank you in advance for your help
解决方案
archivals = new COM('Unreal.ArchivalCtrl', NULL, CP_UTF8) or die ('Unable to Launch Archival Com'); //Open up COM
archivals->ManualStart('localhost', 'test', true, false); //Lets start recording a video on the server
status = new Variant(NULL); //Set variant var to nothing
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