游戏采用USB连接，通过OTG线视频在Android的？ [英] Play Video using connected USB via OTG cable in Android?

问题描述

我想问一下，有其中用户可以连接USB通过OTG线设备到Android和发挥它包含媒体（特别是视频），可用的应用程序。

I want to ask that there are application available in which user can connect USB to Android via OTG cable device and play the media (specially videos) contained by it.

我已经做了广播接收器检测到连接的USB，我​​想也可以参考的内容。我用这code段。

i have made a Broadcast Receiver to detect the attached USB, i want to read the content also. I am using this code snippet.

                    private final BroadcastReceiver mUsbReceiver = new BroadcastReceiver() {

                            public void onReceive(Context context, Intent intent) {
                                String action = intent.getAction();
                                if (UsbManager.ACTION_USB_DEVICE_DETACHED.equals(action)) {
                                    synchronized (this) {
                                        UsbDevice device = (UsbDevice)intent.getParcelableExtra(UsbManager.EXTRA_DEVICE);

                                        if(device != null){
                                              //                        
                                            Log.d("1","DEATTCHED-" + device);
                                          }
                                    }
                                }
                    //
                                if (UsbManager.ACTION_USB_DEVICE_ATTACHED.equals(action)) {
                                    synchronized (this) {
                                        UsbDevice device = (UsbDevice)intent.getParcelableExtra(UsbManager.EXTRA_DEVICE);
                                        if (intent.getBooleanExtra(UsbManager.EXTRA_PERMISSION_GRANTED, false)) {

                                            if(device != null){
                                              //

                                                Log.d("1","ATTACHED-" + device);
                                           }
                                        } 
                                        else {
                                            PendingIntent mPermissionIntent;
                                            mPermissionIntent = PendingIntent.getBroadcast(MainActivity.this, 0, new Intent(ACTION_USB_PERMISSION), PendingIntent.FLAG_ONE_SHOT);                       
                                            mUsbManager.requestPermission(device, mPermissionIntent);

                                        }                   

                                    }
                                }
                    //
                                if (ACTION_USB_PERMISSION.equals(action)) {
                                    synchronized (this) {
                                        UsbDevice device = (UsbDevice)intent.getParcelableExtra(UsbManager.EXTRA_DEVICE);
                                        if (intent.getBooleanExtra(UsbManager.EXTRA_PERMISSION_GRANTED, false)) {

                                            if(device != null){
                                              //

                                                Log.d("1","PERMISSION-" + device);
                                           }
                                        }                   
                                    }
                                }           
                            }
                        };  

我想提出这样一种应用。

I want to make such kind of application.

做任何有关于一些想法？

Do anyone have some idea about that?

推荐答案

经过多日研究，我已经找到了解决办法

After researches of many days i have found the solution

https://github.com/1hakr/AnExplorer

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