如何编写一个Prolog代码，接受来自用户的CGPA输入并确定该CGPA的级别 [英] how to Write a Prolog code that accepts input of CGPA from user and determines the level of that CGPA
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问题描述
Write a Prolog code
that accepts input of CGPA from user and determines the level
of that CGPA; > 0 and <
2.00 as "poor", >= 2.00 and < 3.00 as "good" and >= 3.00 as
"excellent". The example of
output for the Prolog code is as follows:
?- run.
Enter your CGPA: 1.60.
Your CGPA is poor.
?- run.
Enter your CGPA: 2.00.
Your CGPA is good.
?- run.
Enter your CGPA: 3.80.
Your CGPA is
excellent.
推荐答案
CGPA; > 0 and <
2.00 as "poor", >= 2.00 and < 3.00 as "good" and >= 3.00 as
"excellent". The example of
output for the Prolog code is as follows:
?- run.
Enter your CGPA: 1.60.
Your CGPA is poor.
?- run.
Enter your CGPA: 2.00.
Your CGPA is good.
?- run.
Enter your CGPA: 3.80.
Your CGPA is
excellent.
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